CODEWITHSUNDEEP
pythonlistsorting
Diaco
Diaco

Reputation: 251

Python - Sorting Lists

I am trying to sort a list by multiple conditions using this code.

lis = sorted([lsDataSorted[i:i+8] for i in range(0,len(lsDataSorted),8)],key=lambda x:(x[7],int(x[5])-int(x[6]),x[5],x[0]),reverse=True)

Now, we don't need to bother talking about what each object is, but we see that I have an "reverse" sorting function. Now, my last condition x[0] happens to be a list of names. By using the reverse=True, we know that the sorting will be in reverse order (z-a). My question is, can I "reverse" back to normal only for the last condition? If yes, then how?

Upvotes: 1

Views: 140

Answers (1)

Alex Martelli
Alex Martelli

Reputation: 882731

I would recommend wrapping each chunk of lsDataSorted into a custom class that will enforce comparison by your complex condition. For example:

import functools

@functools.total_ordering
class Compare(object):
    def __init__(self, chunk):
        self.x = chunk[7], int(chunk[5]) - int(chunk[6]), chunk[5]
        self.y = chunk[0]
    def __eq__(self, other):
        return (self.x==other.x) and (self.y==other.y)
    def __lt__(self, other):
        if self.x != other.x:
            return self.x < other.x
        return self.y > other.y

Now,

lis = sorted([lsDataSorted[i:i+8]
              for i in range(0,len(lsDataSorted),8)],
              key=Compare, reverse=True)

should give you the mixed complex sorting you're apparently looking for.

Upvotes: 4

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