CODEWITHSUNDEEP
pythonregex
modarwish
modarwish

Reputation: 495

Python: How can I use a regex to split sentences to new lines, and then separate punctuation from words using whitespace?

I have the following input:

input = "I love programming with Python-3.3! Do you? It's great... I give it a 10/10. It's free-to-use, no $$$ involved!"

First, every sentence should be moved to a new line. Then, all of the punctuation should be separated from the words EXCEPT for "/", " ' ", "-", "+" and "$".

So the output should be:

"I love programming with Python-3 . 3 ! 
Do you ?  
It's great . . . 
I give it a 10/10 . 
It's free-to-use , no $$$ involved !"

I used the following code:

>>> import re
>>> re.sub(r"([\w/'+$\s-]+|[^\w/'+$\s-]+)\s*", r"\1 ", input)
"I love programming with Python-3 . 3 ! Do you ? It's great ... I give it a 10/10 . It's free-    to-use , no $$$ involved ! "

But the problem is that it does not separate sentences into new lines. How can I use a regex to do that before I create whitespace between punctuation and characters?

Upvotes: 2

Views: 2677

Answers (2)

vks
vks

Reputation: 67968

([!?.])(?=\s*[A-Z])\s*

You can use this regex to create sentences before your regex.See demo.Replace by \1\n.

https://regex101.com/r/sH8aR8/5

x="I love programming with Python-3.3! Do you? It's great... I give it a 10/10. It's free-to-use, no $$$ involved!"
print re.sub(r"([!?.])(?=\s*[A-Z])",r"\1\n",x)

EDIT:

(?<![A-Z][a-z])([!?.])(?=\s*[A-Z])\s*

Try this.See demo for your different set of data.

https://regex101.com/r/sH8aR8/9

Upvotes: 2

nu11p01n73R
nu11p01n73R

Reputation: 26667

Something like

>>> import re
>>> from string import punctuation
>>> print re.sub(r'(?<=['+punctuation+'])\s+(?=[A-Z])', '\n', input)
I love programming with Python-3.3!
Do you?
It's great...
I give it a 10/10.
It's free-to-use, no $$$ involved!

Upvotes: 2

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