CODEWITHSUNDEEP
phphtmlformsecho
sam
sam

Reputation: 21

My echo statement wont show in html lines

This is my code. I'm trying to print the comments on my site. The query and everything works since I tried it in an empty project but here it doesn't echo. The comments update in the database but they just don't show. What am I missing?

<h1>Leave a comment below!</h1>
<?php

$find_comments = mysql_query("SELECT * FROM comments");

if ($find_comments) {  
    while ($row = mysql_fetch_assoc($find_comments)) {
        $comment_name = $row['name'];
        $comment = $row['comment']; 
        echo "<p>'$comment_name' - '$comment'</p>"; 
    }
}

if(isset($_GET['error'])) {
    echo "<p>100 per limit";
}

?>
<form action="post_comments.php" method="post">
    <p>Your Name: </p>
    <input  type="text" name="name" size="40" maxlength="30" placeholder="Enter name..." </input><br><p>
    <p>Your Email: </p>
    <input  type="text" name="email" size="40" maxlength="30" placeholder="Enter email..." </input><br><p>
    <p>Your comment: </p>
    <textarea  type="text" name="comment" cols="50" rows="10" placeholder="Enter comment..."></textarea><br><p>      
    <input  type="submit" name="submit" value="Submit comment!" ></input>
</form>

Upvotes: 2

Views: 117

Answers (3)

Roh&#236;t J&#237;ndal
Roh&#236;t J&#237;ndal

Reputation: 27192

Try this it will work :

Use

"<p>".$comment_name." - ".$comment."</p>";

instead of

"<p>'$comment_name' - '$comment'</p>";

Upvotes: 0

Priyank
Priyank

Reputation: 3868

echo "<p>".$comment_name."-".$comment."</p>";

Upvotes: -1

user3837170
user3837170

Reputation:

Your variable name is in single quote, it must me concat or place in double quote..

For Ex

            echo "<p>$comment_name-$comment</p>";

or

            echo "<p>".$comment_name."-".$comment</p>";

Upvotes: 2

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