CODEWITHSUNDEEP
bashvariablesmultiple-choice
Viktor
Viktor

Reputation: 81

Bash: Multiple choices put into one variable/array

I am trying to figure out the code for this scenario:

Mix your favourite fruit:
1 Apples
2 Pears
3 Plums
4 Peach
5 Pineapple
6 Strawberry
7 All
8 None

Selection:146

Your cocktail will contain: Apples Peach Strawberry

My limited knowledge can do one at time:

echo "Mix your favourite fruit:
1 Apples
2 Pears
3 Plums
4 Peach
5 Pineapple
6 Strawberry
7 All
8 None"

echo Selection:
read selection

case $selection in
1)
mix=Apples
;;
2)
mix=Pears
;;
..
..
12)
mix="Aples Pears"
;;
7)
mix=123456(this is wrong)
;;
8)
mix=no fruits
;;
esac

echo Your cocktail will contain: $mix

I suppose perhaps I could be adding each number entered into array? Then perhaps case esac loop won't be the best solution?

Upvotes: 1

Views: 176

Answers (1)

John Kugelman
John Kugelman

Reputation: 361605

You could store the fruits in an array, and use the == operator with [[ to check for wildcard matches.

mix=()

[[ $selection == *[17]* ]] && mix+=(Apples)
[[ $selection == *[27]* ]] && mix+=(Pears)
[[ $selection == *[37]* ]] && mix+=(Plums)
...

echo "Your cocktail will contain: ${mix[@]:-no fruits}"

If $selection contains 1 or 7, add "Apples" to the array. If it contains 2 or 7, add "Pears". And so on.

The :- part substitutes the string "no fruits" if the array is empty.

Upvotes: 3

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