Reputation: 21
I've got 3 functions, oe1(n)
, oe2(n)
and oe3(n)
.
I want to create a matrix representing the function values.
The structure of the matrix should be like this:
A = [oe1(0) oe2(0) oe3(0); oe1(1) oe2(1) od3(1); ...... ; oe1(N-1), oe2(N-1), oe3(N-1)];
I've tried filling it with a for
loop, but it does not work.
Is there a standard Matlab operation for this? I really can't figure out how to do it.
Anders.
oe1(n1) = sin(2*pi*F*n1+phi)
oe2(n1) = ones(length(n1),1);
oe3(n1) = n1*Ts
pol = (oe2)'
vector_x = [a; b; c];
vector_veardier = [oe1(n1), 1, oe3(n1)]
xi = 1:N-1;
for i = 2:N-1;
for j = 1:3
vector_veardier(i, j) = oe1(j);
end
end
Upvotes: 1
Views: 1848
Reputation: 3068
Do your functions accept vectors? If so you can use:
A = [oe1((1:N)'), oe2((1:N)'), oe3((1:N)')];
but otherwise you might have to use arrayfun
:
A = [arrayfun(@oe1, (1:N)'), arrayfun(@oe2, (1:N)'), arrayfun(@oe3, (1:N)')];
Note that in your provided code you have not defined oeN as functions, but as some kind of array with a value inserted at position n1.
One way to do it with a for loop would however be:
A = zeros(N,3);
for i = 1:N,
A(i,:) = [oe1(i), oe2(i) oe3(i)];
end
Upvotes: 3