Reputation: 67177
I have a confusing behaviour with the memory alignment of structure elements. Consider these two structures:
typedef struct s_inner {
unsigned long ul1;
double dbl1;
fourth_struct s4;
unsigned long ul2;
int i1;
} t_inner;
typedef struct s_outer {
other_struct member1; /* 4-byte aligned, 40 bytes in terms of sizeof() */
unsigned long member2;
t_inner member3; /* see above */
} t_outer;
When I inspect the memory layout of t_outer, I could see that the elements of member1
are 4-byte aligned, just as I would expect it.
Also the memory layout of member3
is as expected: ul1
has 4 padding bytes attached so that dbl1
is aligned on an 8-byte border (normal on Win32).
However, when I inspect the memory layout of member2
, I could see that this member has 4 padding bytes attached to it.
Could anyone explain why on earth member2
receives padding bytes? My expectation was that member2
does not carry a padding.
Edit 1:
See this memory dump. Before filling the structure elements, I've memset
'd the whole t_outer
structure with p
's:
member1
member2
member3
dbl1
within member3
Constraints
other_struct
should not matter here, it's a 40-byte sized 4-byte aligned structureUpvotes: 1
Views: 206
Reputation: 181824
The VS2012 docs describe its padding behavior. In particular, they specify that the alignment requirement for a struct
is the largest alignment requirement of any of its members. Member member3
's type t_inner
has a member of type double
, with an 8-byte alignment requirement, therefore member3
overall has an 8-byte alignment requirement (and, also, t_outer
has an 8-byte alignment requirement). Padding is required between member2
and member3
to obtain 8-byte alignment of member3
.
Upvotes: 2
Reputation: 942408
so that dbl1 is aligned on an 8-byte border
Sure. But that alignment guarantee means bupkis if the structure itself is not aligned to 8 as well. Which is a guarantee that's normally provided by the compiler's address choices for the data section and the stack frame. Or the memory allocator. All guarantee at least alignment to 8.
But when you embed the structure inside s_outer then those 4 bytes of padding before member3 (not after member2) are required to get the alignment guarantee back.
Also note that a structure can have padding after the last member. Which may be required to ensure that members are still aligned when the structure is stored in an array. Same reason.
Upvotes: 2