CODEWITHSUNDEEP
jsonjackson
ps0604
ps0604

Reputation: 1071

Jackson JSON: Filters declared within filters - how to ignore the child filter?

I'm getting an exception when a filter is declared within a filter. For example, given these classes (note that Parent has a Child member):

@JsonFilter("Parent")
public class Parent {
    private String id;
    private String name;
    private Child child;
    private String other1;
    private String other2;
    // other fields
}

@JsonFilter("Child")
public class Child {
    private String id;
    private String name;
    // other fields
}

When I generate JSON of class Child using filters I have no problems. But when I generate JSON of class Parent using filter this way:

ObjectMapper mapper = new ObjectMapper().setVisibility(JsonMethod.FIELD, Visibility.ANY);

String[] ignorableFieldNames = { "other1", "other2" };

FilterProvider filters = new SimpleFilterProvider().
addFilter("Parent",SimpleBeanPropertyFilter.serializeAllExcept(ignorableFieldNames));

mapper.filteredWriter(filters).writeValueAsString(object);

I get the error No filter configured with id 'Child'. I understand that since Child is declared in Parent and both have the @JsonFilter annotation, I get the error because I only use the Parent filter. But I need the annotation in both classes, as I also run the filter only on the Child class in a different program. What's the workaround?

Upvotes: 1

Views: 1235

Answers (1)

ps0604
ps0604

Reputation: 1071

This is the answer: you append addFilter two or more times for each annotated filter: 

String[] ignorableFieldNames1 = { "other1", "other2" };
String[] ignorableFieldNames2 = { "other3", "other4" };

FilterProvider filters = new SimpleFilterProvider().     
addFilter("Parent",SimpleBeanPropertyFilter.serializeAllExcept(ignorableFieldNames1))
addFilter("Child",SimpleBeanPropertyFilter.serializeAllExcept(ignorableFieldNames2));

Upvotes: 2

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