CODEWITHSUNDEEP
linuxbashunixawksed
FireHawk2300
FireHawk2300

Reputation: 97

sed command to strip a match found

I have a file "fruit.xml" that looks like the below:

FRUIT="Apples"
FRUIT="Bananas"
FRUIT="Peaches"

I want to use a single SED line command to find all occurrences of NAME=" and I want strip the value between the "" from all the matches found.

So the result should look like:

Apples
Bananas
Peaches

This is the command I am using:

sed 's/.*FRUIT="//' fruit.xml

The problem is that it leaves the last " at the end of the value I need. eg: Apples".

Upvotes: 0

Views: 512

Answers (5)

NeronLeVelu
NeronLeVelu

Reputation: 10039

assuming 1 occurence per value and with this format

sed 's/.*="//;s/".*$//' fruit.xml

Upvotes: 0

Arnab Nandy
Arnab Nandy

Reputation: 6712

Use a simple cut command

cut -d '"' -f2 fruits.xml

Output:

Apples
Bananas
Peaches

Upvotes: 0

Biber
Biber

Reputation: 727

Try this, this replaces the line with the founded fruit in the quotes:

sed 's/.*FRUIT="\(.*\)"/\1/' test.xml

Upvotes: 0

Avinash Raj
Avinash Raj

Reputation: 174806

This would be enough if you want to keep the leading spaces,

sed 's/\bFRUIT="\([^"]*\)"/\1/' fruit.xml

OR

sed 's/\bFRUIT="\|"//g' fruit.xml

Upvotes: 1

fedorqui
fedorqui

Reputation: 290165

Just catch the group and print it back: catch everything from " until another " is found with the () (or \(...\) if you don't use the -r option). Then, print it back with \1:

$ sed -r 's/.*FRUIT="([^"]*)"/\1/' file
Apples
Bananas
Peaches

You can also use field separators with awk: tell awk that your field separators are either FRUIT=" or ". This way, the desired content becomes the 2nd field.

$ awk -FS='FRUIT="|"' '{print $2}' file
Apples
Bananas
Peaches

To make your command work, just strip the " at the end of the line:

$ sed -e 's/.*FRUIT="//' -e 's/"$//' file
      ^^                 ^^^^^^^^^^^
      |                  replace " in the end of line with nothing
      -e to  allow you use multiple commands

Upvotes: 5

Related Questions