CODEWITHSUNDEEP
cstringintstrtol
user2973468
user2973468

Reputation: 45

Int array to string for strtol

I want to get 

int sign[8]= {0,1,0,1,0,1,1,1};

to use on strtol function like

char c = (char) strtol(sign, NULL, 2);
printf("%c\n", c);

I have no idea how to cast sign to use in strol. When I'm using 

 c = (char) strtol("01010111", NULL, 2);

everything is ok and I want to get such result.

Please help :)

Upvotes: 1

Views: 1281

Answers (2)

unwind
unwind

Reputation: 399871

The problem is that sign is not a string, it's an array of small integers.

You can interpret them directly as bits and convert the array into a number, there's no point in going via strtol() (and, in fact, it's rather un-idiomatic in C to do it your way).

Just loop:

unsigned int array_to_int(const int *bits, size_t num_bits)
{
  unsigned int ret = 0, value = 1;
  for(; num_bits > 0; --num_bits, value *= 2)
    ret += value * bits[num_bits - 1];
  return ret;
}

Upvotes: 2

Iharob Al Asimi
Iharob Al Asimi

Reputation: 53006

You need to change this

int sign[8]= {0,1,0,1,0,1,1,1};

to 

char sign[9]= {'0','1','0','1','0','1','1','1','\0'};

the way you had it you was using the ascii value 1 instead if the character '1', and you should add a null terminating byte '\0' so the array can be used as a string.

And then, you can

char c = (char) strtol(sign, NULL, 2);
printf("%c\n", c);

Upvotes: 2

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