Reputation: 31
I have a trouble with VBA. I need to calculate variance for array. But array in for loops, and if I use Next i
it will increment i
by 1. So I always have to face with error messages from VBA.
Here is my code:
Function cal_var(dta As Variant)
Dim N, i, j As Integer
Dim tre() As Double
N = UBound(dta)
Dim vec_var() As Integer
ReDim vec_var(1 To N)
For i = 1 To N
j = 1
ReDim tre(1 To i)
For j = 1 To i
tre(j) = dta(j)
Next j
vec_var(i) = Application.WorksheetFunction.Var_P(tre)
Next i
cal_var = vec_var
End Function
The following Sub
checks my function
Sub test()
Dim b(1 To 5) As Integer
Dim a As Double
b(1) = 1
b(2) = 2
b(3) = 3
b(4) = 4
b(5) = 5
a = cal_var(b)
MsgBox a
End Sub
Upvotes: 0
Views: 7692
Reputation: 15561
Your subs contain a number of type mismatches, other errors, and unnecessary code.
If I follow you, you mean to obtain a sequence of variances, by partially including elements of your array. For that task, check code below.
' See http://www.cpearson.com/excel/passingandreturningarrays.htm
Function cal_var(dta() As Integer) As Double()
Dim N, i, j As Integer
Dim tre() As Double
N = UBound(dta)
Dim vec_var() As Double
ReDim vec_var(1 To N)
For i = 1 To N
ReDim Preserve tre(1 To i)
tre(i) = dta(i)
vec_var(i) = Application.WorksheetFunction.Var_P(tre)
Next i
cal_var = vec_var()
End Function
Sub test()
Dim b(1 To 5) As Integer
Dim a() As Double
b(1) = 1
b(2) = 2
b(3) = 3
b(4) = 4
b(5) = 5
a = cal_var(b)
' See http://www.mrexcel.com/forum/excel-questions/562103-display-array-msgbox.html
Dim myArray() As Variant
Dim txt As String
Dim i As Long
For i = LBound(a) To UBound(a)
txt = txt & a(i) & vbCrLf
Next i
MsgBox txt
End Sub
See
Passing And Returning Arrays With Functions
Upvotes: 0
Reputation: 7918
Based on the task description, a simple VBA formula will return a variance of the array (b
as per your sample):
Function cal_var(dta As Variant)
cal_var = Application.WorksheetFunction.Var_P(dta)
End Function
Sub test()
Dim b(1 To 5) As Integer
Dim a As Double
b(1) = 1
b(2) = 2
b(3) = 3
b(4) = 4
b(5) = 5
a = cal_var(b)
MsgBox a
End Sub
It correctly returns the value of 2.
Hope this will help.
Upvotes: 2