CODEWITHSUNDEEP
java
askManiac
askManiac

Reputation: 167

Java Adding and Subtracting of Time

I have four dates and I wanted to get the total...

EXAMPLE

timeInAM=9:00

timeOutAM=12:00

timeInPM=13:00

timeOutPM=18:00

I wanted to make total=(timeOutAM-timeInAM)+(timeOutPM-timeInPM) that would result in total=8:00

but it gives me '16:00:00'

Here's what I did: DATE

SimpleDateFormat tf24=new SimpleDateFormat("HH:mm");
Date timeInAM=new Date();
Date timeOutAM=new Date();
Date timeInPM=new Date();
Date timeOutPM=new Date();
long total;

timeInAM=tf24.parse(tblWorkPeriod.getValueAt(i, 1).toString());
timeOutAM=tf24.parse(tblWorkPeriod.getValueAt(i, 2).toString());
timeInPM=tf24.parse(tblWorkPeriod.getValueAt(i, 3).toString());
timeOutPM=tf24.parse(tblWorkPeriod.getValueAt(i, 4).toString());
total=(timeOutAM.getTime()-timeInAM.getTime())+(timeOutPM.getTime()-timeInPM.getTime());
System.out.println(tf24.format(new Date(total)));

CALENDAR

Calendar timeInAM=Calendar.getInstance();
Calendar timeOutAM=Calendar.getInstance();
Calendar timeInPM=Calendar.getInstance();
Calendar timeOutPM=Calendar.getInstance();
Calendar total=Calendar.getInstance();

SimpleDateFormat tf24=new SimpleDateFormat("HH:mm");

timeInAM.setTime(tf24.parse(tblWorkPeriod.getValueAt(i, 1).toString()));
timeOutAM.setTime(tf24.parse(tblWorkPeriod.getValueAt(i, 2).toString()));
timeInPM.setTime(tf24.parse(tblWorkPeriod.getValueAt(i, 3).toString()));
timeOutPM.setTime(tf24.parse(tblWorkPeriod.getValueAt(i, 4).toString()));
long sum=(timeOutAM.getTimeInMillis()-timeInAM.getTimeInMillis())+(timeOutPM.getTimeInMillis()-timeInPM.getTimeInMillis());
total.setTimeInMillis(sum);
System.out.println("total : "+tf24.format(total.getTime()));

Upvotes: 0

Views: 87

Answers (3)

Lucas Baizer
Lucas Baizer

Reputation: 325

I'm not sure if I understand your question, but here:

You can try to use:

double timeInAMint = Double.parseDouble(timeInAM);
double timeOutAMint = Double.parseDouble(timeoutAM);
double timeInPMint = Double.parseDouble(timeInPM);
double timeOutPMint = Double.parseDouble(timeOutPM);
double sum = timeInAMint + timeOutAMint + timeInPMint + timeOutPMint;
System.out.println("Sum: " + sum);

Upvotes: 0

Nuno
Nuno

Reputation: 496

You can give a try to JodaTime library (if you can use other libraries). With the following you can achieve what you need by calling LocalTime::minusHours and similar commands:

LocalTime timeInAM=new LocalTime(hourOfDay, minuteOfHour);
LocalTime timeOutAM=new LocalTime(hourOfDay, minuteOfHour);
LocalTime timeInPM=new LocalTime(hourOfDay, minuteOfHour);
LocalTime timeOutPM=new LocalTime(hourOfDay, minuteOfHour);

LocalTime amInterval = timeOutAM.minusHours(timeInAM.getHourOfDay()).minusMinutes(timeInAM.getMinuteOfHour());
LocalTime pmInterval = timeOutPM.minusHours(timeInPM.getHourOfDay()).minusMinutes(timeInPM.getMinuteOfHour());

LocalTime total = pmInterval.plusHours(amInterval.getHourOfDay()).plusMinutes(amInterval.getMinuteOfHour());

Use a proper DateTimeFormatter to parse/print the dates in LocalTime.

Upvotes: 2

Ravindra HV
Ravindra HV

Reputation: 2608

Try using a Calendar instance.

Edit : Sample implementation.

Calendar timeInBeforeBreak = Calendar.getInstance();
timeInBeforeBreak.clear();

Calendar timeOutBeforeBreak = Calendar.getInstance();
timeOutBeforeBreak.clear();

timeInBeforeBreak.add(Calendar.HOUR_OF_DAY, 9);
timeInBeforeBreak.add(Calendar.MINUTE, 30);
timeOutBeforeBreak.add(Calendar.HOUR_OF_DAY, 11);
timeOutBeforeBreak.add(Calendar.MINUTE, 30);

long timeMillis = timeOutBeforeBreak.getTimeInMillis() - timeInBeforeBreak.getTimeInMillis();

System.out.println("Hours :"+timeMillis/1000/60/60);

Upvotes: 0

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