Sending email with sendgrid [Node.js]

Question

i'm using the following code to send two specific emails, one for the reservation client and other for me:

sendgrid.send({
        to:         "client@client.com",
        from:       "me@me.com",
        subject:    "Register confirmation",
        html:           "Some HTML",
    },
    function(err, json) {
        if (err) {
            return console.error(err);
        } 
        else {
            next();
        }
});

sendgrid.send({
        to:         "me@me.com",
        from:       "newRegister@me.com",
        subject:    "NEW RESERVATION!",
        html:       "SOME TEXT OR HTML",
    },
    function(err, json) {
        if (err) {
            return console.error(err);
        } 
        else {
            next();
        }
});

Can i improve this? There is some much duplication.

Answer 1

Just replace the API key you get from https://app.sendgrid.com/settings/api_keys. (Create API Key)

..and install @sendgrid/mail package of course.

npm i @sendgrid/mail --save

const sgMail = require("@sendgrid/mail");

const SENGRID_API_KEY = 'Here_Paste_Your_Key'; 
sgMail.setApiKey(SENGRID_API_KEY);

const msg = {
    to: 'to@email.com',
    from: 'from@email.com',
    subject: "Test Subject",
    text: 'Hello World!',
    html: '<strong>Hello World!</strong>',
};

sgMail.send(msg, function(err, info) {
    if (err) {
        console.log("Email Not Sent.");
    } else {
        console.log("Email Sent Success.");
    }
});

Answer 2

You could specify yourself as a recipient and you would get the exact email your client is receiving. If you use the SMTPAPI, the user wouldn't see your email address and neither would you see theirs. To use that in the Node.js lib, you can do so this way:

var sendgrid = require('sendgrid')('api_user', 'api_pwd');
var email = sendgrid.Email();
email.smtpapi.addTo('client@email.com');
email.smtpapi.addTo('your@notification.email');
email.setSubject('Register confirmation');
email.setHtml('booking numbah');
email.setFrom('your@email.com');
sendgrid.send(email, function(err, json) {
   console.log(arguments);
});

Hope that helps!