CODEWITHSUNDEEP
javahtmlseleniumweb-scrapingcss-selectors
klib
klib

Reputation: 697

Locating an Element in Selenium

I am attempting to locate a link using Selenium in java. I want to use the web driver to click on the link. The element is a number that is a link to another page. This is the section of html containing the elements I would like to locate:

<tr class="DataGridPagerStyle">
<td colspan="5">
<span>1</span>
<a href="javascript:__doPostBack('ctl00$ctl62$dgPersonSearchResults$ctl19$ctl01','')">2</a>
<a href="javascript:__doPostBack('ctl00$ctl62$dgPersonSearchResults$ctl19$ctl02','')">3</a>
<a href="javascript:__doPostBack('ctl00$ctl62$dgPersonSearchResults$ctl19$ctl03','')">4</a>
</td>
</tr>

I would like to flip through the pages, therefore I need to locate the "a href" elements. There are sometimes a different number of pages. I attempted to locate and click on these elements using the following java code:

String href = doc.select("tr.DataGridPagerStyle").first().select("a:contains(" + i + ")").first().attr("href");
element = wait.until(ExpectedConditions.visibilityOfElementLocated(By.cssSelector("a[href=" + href + "]")));
element.click();

The href string does contain the right value of the href attribute for a given value of i, however I get this error when running the code:

The given selector a[href=javascript:__doPostBack('ctl00$ctl62$dgPersonSearchResults$ctl19$ctl01','')]
is either invalid or does not result in a WebElement. The following error occurred:
InvalidSelectorError: An invalid or illegal selector was specified

Why is this happening and what is the best way to select these elements?

Upvotes: 0

Views: 133

Answers (1)

alecxe
alecxe

Reputation: 473803

You can find the links by linkText():

link = doc.select("tr.DataGridPagerStyle").first().findElement(By.linkText(i))
link.click()

Upvotes: 3

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