Reputation: 45
I have created a new app using the Yahoo API. How can I pass the required headers using CURL functionality? I got this error message when I tried:
<yahoo:error xml:lang="en-US"><yahoo:description>Please provide valid credentials. OAuth oauth_problem="unable_to_determine_oauth_type", realm="yahooapis.com"</yahoo:description></yahoo:error>
How can I pass the required headers in this code:
$url ="http://fantasysports.yahooapis.com/fantasy/v2/team/223.l.431.t.1";
$ch = curl_init(); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_URL, $url);
//get the url contents
$data = curl_exec($ch);
//execute curl request curl_close($ch);
$xml = simplexml_load_string($data);
print_r($xml);
exit;
Upvotes: 1
Views: 1980
Reputation: 53928
Once you'd obtained an OAuth 2.0 access token, use it in the following code:
$token = "<token>";
$url = "https://fantasysports.yahooapis.com/fantasy/v2/team/223.l.431.t.1?format=json";
$headers = array(
'Authorization: Bearer ' . $token,
);
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
$response = curl_exec($ch);
curl_close($ch);
$json = json_decode($response);
print_r($json);
Notice that it presents the token in an Authorization
HTTP header over a secure transport channel using the https
URL scheme and requests to return the content as JSON using the format
URL query parameter.
Upvotes: 1