CODEWITHSUNDEEP
iosswiftcastingcompiler-errors
user3606054
user3606054

Reputation: 591

AnyObject is not convertible to 'String'

I am getting the following error AnyObject' is not convertible to 'String'. I am getting this error on the line if (answerArray != NSNull() && answerArray != nil)

I try casting it as String, but it didn't fix the problem. I posted the whole code below.

 let answerArray : AnyObject = jsonparser.objectWithString(answer)
 if (answerArray != NSNull()  && answerArray != nil) {

}

Upvotes: 0

Views: 1970

Answers (2)

tng
tng

Reputation: 4336

My guess would be the error is with answerArray != nil - Swift is silly in that the error it returns here is "not convertible to String". More helpful would be answerArray is not Optional.

And that's your problem - you have let answerArray : AnyObject... - and AnyObject is not Optional. In Swift, 'answerArray' is never 'nil', because only Optional types can be nil.

Without looking at what jsonparser.objectWithString does, it's hard for me to correct your code, but in essence, the compiler is telling you that you are checking a non-optional type for nil - which is incorrect.

Upvotes: 0

Antonio
Antonio

Reputation: 72750

My understanding is that jsonparser.objectWithString(answer) is supposed to return an array, basing on the name of the variable it is assigned to.

If it's an array of heterogeneous types, you can attempt a cast to NSArray:

if let answerArray = jsonparser.objectWithString(answer) as? NSArray {
    ...
}

If the array is supposed to contain objects of the same type (let's say Int) instead, then you can try a cast to a swift array:

if let answerArray = jsonparser.objectWithString(answer) as? [Int] {
    ...
}

Note that a non-optional variable can never be nil - and you have declared answerArray as a non-optional.

If you want to check for NSNull, I suggest reading this question and related answer.

Upvotes: 2

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