Reputation: 951
For the following series,
S= Sum[(e^(a*m*n))*((b^(-m)*(n/2)))),{m,1,infinity}]
I get the output:
By the geometric series test, the series converges.
How to get the actual value of the infinite sum?
Kindly help. Thanks in advance.
Upvotes: 0
Views: 1206
Reputation: 93181
Did you actually run the code in Mathematica? You have an extra round bracket. Also infinity
is a user variable. Infinity
(capital I
) is a built in Mathematica symbol:
S = Sum[(e^(a*m*n))*((b^(-m)*(n/2))), {m, 1, Infinity}]
Result:
-((e^(a n) n)/(2 (-b + e^(a n))))
I also suspect that e
is the natural exponent. If so, use the capital E
.
Upvotes: 2