CODEWITHSUNDEEP
androidgoogle-api-client
user971741
user971741

Reputation:

GoogleApiClient connect always fails first time but gets successful second time

I have a google plus login set up for app through GoogleApiClient.

Whenever the app is installed first time and tries to make connection through GoogleApiClient it never gets successful and always end up at onConnectionFailed with result containing:

ConnectionResult{statusCode=SIGN_IN_REQUIRED, resolution=PendingIntent{4130e760: android.os.BinderProxy@4130e700}}

But when second time login its called it gets successful and onConnected hits. Why is that is it possible to make it successful over the first attempt?

Is there something wrong in my Builder parameters?

public void connectGoogleApi() {
    mGoogleApiClient = new GoogleApiClient.Builder(mainAppContext).addConnectionCallbacks(this).addOnConnectionFailedListener(this).addApi(Plus.API).addScope(Plus.SCOPE_PLUS_LOGIN).build();
    mGoogleApiClient.connect();
}

public void onConnectionFailed(ConnectionResult result) {
    if (!result.hasResolution()) {
        GooglePlayServicesUtil.getErrorDialog(result.getErrorCode(), this, 0).show();
        return;
    }

    if (!mIntentInProgress) {
        // Store the ConnectionResult for later usage
        mConnectionResult = result;
        resolveSignInError();
    }

}

Upvotes: 9

Views: 1248

Answers (2)

Tinko
Tinko

Reputation: 502

As official docs says here:

If you are using GoogleApiClient to connect to APIs that require authentication, like Google Drive or Google Play Games, there's a good chance your first connection attempt will fail and your app will receive a call to onConnectionFailed() with the SIGN_IN_REQUIRED error because the user account was not specified.

Upvotes: 2

Piotr Niewinski
Piotr Niewinski

Reputation: 1347

I had the same problem, calling 'connect()' again, this time inside 'onConnected' method fixed it. Strange.

@Override
   public void onConnected(final Bundle arg0) {
   Logger.log("On connected");
   DevicePreferences.getGoogleApiClient().connect();
}

Upvotes: 1

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