Reputation: 5348

Simulate a specific CURL in PostMan

I am using Postman to test some Curl requests to an API server. The API developers gave us the curl command, but I can't send it from the Postman. How to make such a request from the Postman?

curl -X POST "https://api-server.com/API/index.php/member/signin" -d "{"description":"","phone":"","lastname":"","app_version":"2.6.2","firstname":"","password":"my_pass","city":"","apikey":"213","lang":"fr","platform":"1","email":"[email protected]","pseudo":"example"}"

--0xKhTmLbOuNdArY
Content-Disposition: form-data; name="userfile"; filename="profil.jpg"
Content-Type: image/jpeg
Content-Transfer-Encoding: binary

<ffd8ffe0 00104a46 49460001 01010048 ... a00fffd9>

—0xKhTmLbOuNdArY—

Upvotes: 402

Answers (13)

Tnadev

Reputation: 10072

Find the Import button on the top right corner
Select Raw and paste your curl commands click Continue -> Import
You can confirm request URL, params, and headers are imported properly.

Upvotes: 16

Yotic

Reputation: 153

In addition to the others, I can give you a script in C# that converts curl(cmd) from Chrome dev tools into regular curl, which allows you to import it into postman.

string CmdCUrlToPostman(string input)
{
    var lines = 
        input
        .Split("\r\n")
        .ToList();

    for (int l = 0; l < lines.Count; l++)
    {
        var line = lines[l];

        if (line.EndsWith(" ^"))
            lines[l] = line = line.Substring(0, lines[l].Length - 2);

        if (line.StartsWith("  --data-raw"))
            lines[l] = line.Replace("  --data-raw", "  -d");
        else if (line.StartsWith("  --compressed"))
        {
            lines.RemoveAt(l);
            l--;
        }
        else if (line.StartsWith("  -H"))
            lines[l] = 
                line
                .Replace("^\\", "\\")
                .Replace("^\"", "\"");
    }

    return string.Join('\n', lines);
}

Upvotes: 0

SRD

Reputation: 21

Click on import button from upper left
Prompt ask you to enter cURL, raw text and URL and then paste your code
Automatically You can confirm request URL, params, and headers are imported properly.
Click on send button from upper right corner, you can see the response of that cURL

Upvotes: 2

Rakshit Mathpal

Reputation: 11

import from upper left
go to raw text and paste your code
import it
You can confirm request URL, params, and headers are imported properly.

Upvotes: 1

AnandShiva

Reputation: 1339

I solved this by moving to the insomnia app completely.

Open the insomnia app, and paste the CURL request in the URL section of the request page. This accepts CURL with small discrepancies and CURL copied from chrome Copy as CRUL command also.

Upvotes: 0

Onkaar Singh

Reputation: 10453

A simpler approach would be:

Open POSTMAN
Click on "import" tab on the upper left side.
Select the Raw Text option and paste your cURL command.
Hit import and you will have the command in your Postman builder!
Click Send to post the command

Upvotes: 984

Derek Liang

Reputation: 1222

When you use Chrome copy as cURL (bash) and import in Postman, you need to do the following things:

Remove --compressed option
Replace --data-raw with -d

Otherwise you will get invalid format for cURL error.

Upvotes: 10

akshay_sushir

Reputation: 1841

As per the above answers, it works well.

If we paste curl requests with Authorization data in import, Postman will set all headers automatically. We only just pass row JSON data in the request body if needed or Upload images through form-data in the body.

This is just an example. Your API should be a different one (if your API allows)

curl -X POST 'https://verifyUser.abc.com/api/v1/verification' \
    -H 'secret: secret' \
    -H 'email: [email protected]' \
    -H 'accept: application/json, text/plain, */*' \
    -H 'authorizationtoken: bearer' \
    -F 'referenceFilePath= Add file path' \
    --compressed

Upvotes: 0

Shekhar

Reputation: 623

As mentioned in multiple answers above you can import the cURL in POSTMAN directly. But if URL is authorized (or is not working for some reason) ill suggest you can manually add all the data points as JSON in your postman body. take the API URL from the cURL.

for the Authorization part- just add an Authorization key and base 64 encoded string as value.

example:

curl -u rzp_test_26ccbdbfe0e84b:69b2e24411e384f91213f22a \ https://api.razorpay.com/v1/orders -X POST \ --data "amount=50000" \ --data "currency=INR" \ --data "receipt=Receipt #20" \ --data "payment_capture=1" https://api.razorpay.com/v1/orders

{ "amount": "5000", "currency": "INR", "receipt": "Receipt #20", "payment_capture": "1" }

Headers: Authorization:Basic cnpwX3Rlc3RfWEk5QW5TU0N3RlhjZ0Y6dURjVThLZ3JiQVVnZ3JNS***U056V25J where "cnpwX3Rlc3RfWEk5QW5TU0N3RlhjZ0Y6dURjVThLZ3JiQVVnZ3JNS***U056V25J" is the encoded form of "rzp_test_26ccbdbfe0e84b:69b2e24411e384f91213f22a"`

small tip: for encoding, you can easily go to your chrome console (right-click => inspect) and type : btoa("string you want to encode") ( or use postman basic authorization)

Upvotes: 1

Ankit Gupta

Reputation: 786

sometimes whenever you copy cURL, it contains --compressed. Remove it while import->Paste Raw Text-->click on import. It will also solve the problem if you are getting the syntax error in postman while importing any cURL.

Generally, when people copy cURL from any proxy tools like Charles, it happens.

Upvotes: 4

electricalbah

Reputation: 2297

In addition to the answer
1. Open POSTMAN
2. Click on "import" tab on the upper left side.
3. Select the Raw Text option and paste your cURL command.
4. Hit import and you will have the command in your Postman builder!
5. If -u admin:admin are not imported, just go to the Authorization 
   tab, select Basic Auth -> enter the user name eg admin and password eg admin.
This will automatically generate Authorization header based on Base64 encoder

Upvotes: 23

Rito

Reputation: 3290

I tried the approach mentioned by Onkaar Singh,

Open POSTMAN
Click on "import" tab on the upper left side.
Select the Raw Text option and paste your cURL command.
Hit import and you will have the command in your Postman builder!

But the problem is it didn't work for the Apis which requires authorisation.

This was my curl request:

curl -v -H "Accept: application/json" -H "Content-type:
application/json" -X POST -d ' 
{"customer_id":"812122", "event":"add_to_cart", "email": "[email protected]", }' 
-u 9f4d7f5445e7: https://api.myapp.com/api/event

After importing the body got imported correctly, the headers and the Url also got imported. Only the api key 9f4d7f5445e7 which is

-u 9f4d7f5445e7: https://api.myapp.com/api/v1/event

in the curl request did not import.

The way I solved it is, -u is basically used for Authorization. So while using it in Postman, you have to take the API key (which is 9f4d7f5445e7 in this case) and do Base64 Encode. Once encoded it will return the value OWY0ZDdmNTQ0NWU3. Then add a new header, the key name would be Authorization and key value would be Basic OWY0ZDdmNTQ0NWU3. After making that changes, the request worked for me.

There are online Base64 Encoders available, the one I used is http://www.url-encode-decode.com/base64-encode-decode/

Hope it helps!!!

Upvotes: 10

hello_harry

Reputation: 1305

1) Put https://api-server.com/API/index.php/member/signin in the url input box and choose POST from the dropdown

2) In Headers tab, enter:

Content-Type: image/jpeg

Content-Transfer-Encoding: binary

3) In Body tab, select the raw radio button and write:

{"description":"","phone":"","lastname":"","app_version":"2.6.2","firstname":"","password":"my_pass","city":"","apikey":"213","lang":"fr","platform":"1","email":"[email protected]","pseudo":"example"}

select form-data radio button and write:

key = name Value = userfile Select Text key = filename Select File and upload your profil.jpg

Upvotes: 9

Simulate a specific CURL in PostMan

Answers (13)

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