Reputation: 269
I am planning to flatten my START END dates for customer as shown below.If the date ranges are continuous , I will merge those records . other wise i will keep it as such EG:
Input
Customer START END
A 2000 2001
A 2001 2007
A 2009 2010
A 2011 2015
Expected Output
A 2000 2007
A 2009 2010
A 2011 2015
Using analytical function I was able to tag the records with continuous dates:
--TAG = 1 means continuous
select A *,
CASE WHEN LEAD (START) OVER (PARTITION BY CUSTOMER ORDER BY START,END) = END
OR LAG (END_DT) OVER (PARTITION BY CUSTOMER ORDER BY START,END) = START
THEN 1 ELSE 0 END AS CONT_FLG
From TABLE CUSTOMER
Customer START END CONT_FLG
A 2000 2001 1
A 2001 2007 1
A 2009 2010 0
A 2011 2015 0
But I cannot proceed with min (START) and mAx (END) group by Customer as it will merge the non - continuos values also. Any good suggestions
Upvotes: 2
Views: 59
Reputation: 191245
If you capture the actual lead/lag dates rather than a 0/1, then you get something like this:
select t.*,
case when lag(end_dt) over (partition by customer order by start_dt)
= start_dt then null else start_dt end as adj_start_dt,
case when lead(start_dt) over (partition by customer order by start_dt)
= end_dt then null else end_dt end as adj_end_dt
from t42 t
order by customer, start_dt;
CUSTOMER START_DT END_DT ADJ_START_DT ADJ_END_DT
-------- ---------- ---------- ------------ ----------
A 2000 2001 2000
A 2001 2003
A 2003 2007 2007
A 2009 2010 2009 2010
A 2011 2015 2011 2015
I've split your second record into two adjacent records for effect, so that there is a row here with bot adjusted dates null. You can then remove those with both null, as those reflect records entirely inside a range, and you're left with the start and end dates of each period:
select *
from (
select t.*,
case when lag(end_dt) over (partition by customer order by start_dt)
= start_dt then null else start_dt end as adj_start_dt,
case when lead(start_dt) over (partition by customer order by start_dt)
= end_dt then null else end_dt end as adj_end_dt
from t42 t
)
where adj_start_dt is not null or adj_end_dt is not null
order by customer, start_dt;
CUSTOMER START_DT END_DT ADJ_START_DT ADJ_END_DT
-------- ---------- ---------- ------------ ----------
A 2000 2001 2000
A 2003 2007 2007
A 2009 2010 2009 2010
A 2011 2015 2011 2015
And you can then collapse those with nulls, as the adjacent rows (with lead/lag) are now related:
select distinct customer,
case when adj_start_dt is null then
lag(adj_start_dt) over (partition by customer order by start_dt)
else adj_start_dt end as grp_start_dt,
case when adj_end_dt is null then
lead(adj_end_dt) over (partition by customer order by start_dt)
else adj_end_dt end as grp_end_dt
from (
select t.*,
case when lag(end_dt) over (partition by customer order by start_dt)
= start_dt then null else start_dt end as adj_start_dt,
case when lead(start_dt) over (partition by customer order by start_dt)
= end_dt then null else end_dt end as adj_end_dt
from t42 t
)
where adj_start_dt is not null or adj_end_dt is not null
order by customer, grp_start_dt;
CUSTOMER GRP_START_DT GRP_END_DT
-------- ------------ ----------
A 2000 2007
A 2009 2010
A 2011 2015
Upvotes: 1
Reputation: 132570
Try something like
select customer, min(start), min(end)
from
(
select A *,
CASE WHEN LEAD (START) OVER (PARTITION BY CUSTOMER ORDER BY START,END) = END
OR LAG (END_DT) OVER (PARTITION BY CUSTOMER ORDER BY START,END) = START
THEN 1 ELSE 0 END AS CONT_FLG
From TABLE CUSTOMER
)
group by customer, cont_flg, case when cont_flg=0 then start end
Upvotes: 1