CODEWITHSUNDEEP
javabigdecimal
Ignacio
Ignacio

Reputation: 121

BigDecimal Incorrect Round

I have this result of division:

4893.305785123966785163027491292661448576748

I want to round to 4893.30, but it always returns 4893.31. but when the second decimal will be 6 or more i want to round up.

new BigDecimal("4893.305785123966785163027491292661448576748").setScale(2,BigDecimal.ROUND_HALF_DOWN)); to 4893.31 //BAD

new BigDecimal("4893.305").setScale(2,BigDecimal.ROUND_HALF_DOWN)); to 4893.30 //OK

new BigDecimal("4893.3055").setScale(2,BigDecimal.ROUND_HALF_DOWN)); to 4893.31 //BAD

How does the round work? I want to take in consideration only the value of the second decimal. Any ideas?

Upvotes: 0

Views: 257

Answers (2)

azurefrog
azurefrog

Reputation: 10945

"How does the round work? I want to take in consideration only the value of the second decimal."

It sounds like you want to truncate instead of round.

Instead of using ROUND_HALF_DOWN:

Rounding mode to round towards "nearest neighbor"...

...instead, try using ROUND_DOWN:

Rounding mode to round towards zero. Never increments the digit prior to a discarded fraction (i.e., truncates)...

e.g.

    BigDecimal bd = new BigDecimal("4893.305785123966785163027491292661448576748");
    bd = bd.setScale(2, BigDecimal.ROUND_DOWN);
    System.out.println(bd); // 4893.30

Update to answer question edit

If you want to only take certain decimal places into consideration, that's a truncate followed by a rounding:

    BigDecimal bd = new BigDecimal("4893.305785123966785163027491292661448576748");
    bd = bd.setScale(3, BigDecimal.ROUND_DOWN);       // truncate to 4893.305
    bd = bd.setScale(2, BigDecimal.ROUND_HALF_DOWN);  // round to 2 decimal places
    System.out.println(bd);                           // 4893.30

    bd = new BigDecimal("4893.306785123966785163027491292661448576748");
    bd = bd.setScale(3, BigDecimal.ROUND_DOWN);       // truncate to 4893.306
    bd = bd.setScale(2, BigDecimal.ROUND_HALF_DOWN);  // round to 2 decimal places
    System.out.println(bd);                           // 4893.31

Upvotes: 1

Brian Knoblauch
Brian Knoblauch

Reputation: 21349

Perhaps you're looking for a truncate function at the given scale? The BigDecimal rounding you show is working exactly as designed.

Upvotes: 1

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