CODEWITHSUNDEEP
xmlxslt
Renaud is Not Bill Gates
Renaud is Not Bill Gates

Reputation: 2084

display date in XSLT

In my XML File I have as the following :

<From year="2013" month="--01" day="---04"/>

In My XSLT File I want to display the values of these attributes, so I will have something like this in the output :

04/01/2013

But instead of this, I have this :

---01/--04/2013

This is what I wrote in my XSLT file :

<xsl:value-of select="Period/To/@day" />/<xsl:value-of select="Period/To/@month" />/<xsl:value-of select="Period/To/@year" />

How can I solve this ?

Upvotes: 0

Views: 36

Answers (1)

matthias_h
matthias_h

Reputation: 11416

You could use translate() to remove the-: 

<xsl:value-of select="translate(Period/To/@day,'-','')" />/
<xsl:value-of select="translate(Period/To/@month,'-','')" />/
<xsl:value-of select="Period/To/@year" />

Result:

04/01/2013

translate(value, '-','') just translates/replaces every occurence of - with nothing.

For reference: https://developer.mozilla.org/en-US/docs/Web/XPath/Functions/translate

Upvotes: 2

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