CODEWITHSUNDEEP
javascript
Misha Moroshko
Misha Moroshko

Reputation: 171341

Number of bits in Javascript numbers

I work in Javascript with integer numbers only (mainly adding numbers and shifting them). I wonder how big they can be without loosing any bits.

For example, how big X can be such that 1 << X will represent 2^X ?

Upvotes: 36

Views: 32740

Answers (3)

Marwen Trabelsi
Marwen Trabelsi

Reputation: 4257

All answers are partially wrong - Maybe due the new ES6/ES7 specs - , read why:

First of all, in JavaScript, the representation of the number is 2^53 - 1 that is true for @Luke answer, we can prove that by running Number.MAX_SAFE_INTEGER that will show a big number, then we do log2 to confirm that the number of bits is the same :

Number.MAX_SAFE_INTEGER
// 9007199254740991

Math.log2(9007199254740991)
// 53

enter image description here

However, Bitwise operation are calculated on 32 bits ( 4 bytes ), meaning if you exceed 32bits shifts you will start loosing bits.

Welcome to Javascript!

Upvotes: 17

LukeH
LukeH

Reputation: 269368

All numbers in JavaScript are actually IEEE-754 compliant floating-point doubles. These have a 53-bit mantissa which should mean that any integer value with a magnitude of approximately 9 quadrillion or less -- more specifically, 9,007,199,254,740,991 -- will be represented accurately.

NOTICE: in 2018 main browsers and NodeJS are working also with the new Javascript's primitive-type, BigInt, solving the problems with integer value magnitude.

Upvotes: 42

Syntactic
Syntactic

Reputation: 10961

All numbers in JavaScript are 64-bit (double-precision) floating point numbers.

Here's a description of the format and what values can and can't be represented with it.

Upvotes: 6

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