Reputation: 599
I want to create a clock that count down in hours min and seconds, but for some reason is not working, can somebody help me
def countdown():
times = 1
th = 1
tm = 0
ts = 0
while times != 0:
if (ts>0 or tm>0 or th>0):
print ('it run for ' + str(th) + ' Hours ' + str(tm) + ' Minutes ' + str(ts) + ' Seconds ')
time.sleep(1)
ts = ts - 1
if (ts==0 and (tm>0 or th>0)):
ts = 59
tm = tm - 1
if(ts==0 or tm==0 and th>0):
ts = 59
tm = 59
th = th - 1
if (ts==0 and tm==0 and th==0):
times = 0
else:
print ('stopped')
ts = 0
tm = 0
th = 0
countdown()
thanks
Upvotes: 2
Views: 1137
Reputation: 180391
A much simpler method is would be to use datetime and time.sleep
In a function, where you can pass in days,hours,mins and seconds to countdown from:
from datetime import datetime, timedelta
import time
def countdown(d=0, h=0, m=0, s=0):
counter = timedelta(days=d, hours=h, minutes=m, seconds=s)
while counter:
time.sleep(1)
counter -= timedelta(seconds=1)
print("Time remaining: {}".format(counter))
An example counting down 5 seconds:
In [2]: countdown(s=5)
Time remaining: 0:00:04
Time remaining: 0:00:03
Time remaining: 0:00:02
Time remaining: 0:00:01
Time remaining: 0:00:00
Two hours:
In [3]: countdown(h=2)
Time remaining: 1:59:59
Time remaining: 1:59:58
Time remaining: 1:59:57
Time remaining: 1:59:56
Time remaining: 1:59:55
Time remaining: 1:59:54
Upvotes: 4
Reputation: 249103
import datetime
import time
def countdown():
count = datetime.timedelta(hours=1)
while count:
print ('it run for ' + str(count))
time.sleep(1)
count -= datetime.timedelta(seconds=1)
print ('stopped')
countdown()
Upvotes: 2