CODEWITHSUNDEEP
javanetbeans
sam007
sam007

Reputation: 83

Convert alternate char to uppercase

I am new to java programming. I want to print a string with alternate characters in UpperCase.

String x=jTextField1.getText();
x=x.toLowerCase();
int y=x.length();
for(int i=1;i<=y;i++)
{}

I don't know how to proceed further. I want to do this question with the help of looping and continue function. Help would be appreciated. Thanks.

Upvotes: 0

Views: 23314

Answers (10)

Moein Qureshi
Moein Qureshi

Reputation: 11

public class ClassC {

    public static void main(String[] args) {
        String str = "Hello";
        StringBuffer strNew = new StringBuffer();
        for (int i = 0; i < str.length(); i++) {
            if (i % 2 == 0) {
                strNew.append(Character.toLowerCase(str.charAt(i)));
            } else {
                strNew.append(Character.toUpperCase(str.charAt(i)));
            }
        }
        System.out.println(strNew);
    }
}

Upvotes: 0

DecipherX
DecipherX

Reputation: 46

Java 8 Solution:

static String getMixedCase(String str) {
    char[] chars = str.toCharArray();
    return IntStream.range(0, str.length())
                    .mapToObj(i -> String.valueOf(i % 2 == 1 ? chars[i] : Character.toUpperCase(chars[i])))
                    .collect(Collectors.joining());
}

Upvotes: 0

Anne Lingesh
Anne Lingesh

Reputation: 65

public static void main(String[] args)
{
    Scanner sc=new Scanner(System.in);
    System.out.println("Enter Stirng");
    String str=sc.nextLine();
    for(int i=0;i<str.length();i++)
    {
        if(i%2==0)
        {
            System.out.print(Character.toLowerCase(str.charAt(i)));
        }
        else
        {
            System.out.print(Character.toUpperCase(str.charAt(i)));
        }
    }

    sc.close();
}

Upvotes: 0

Matt
Matt

Reputation: 5694

Using as much of your code as I could, here's what I got. First I made a string called build that will help you build your resulting string. Also, I changed the index to go from [0,size-1] not [1,size]. Using modulo devision of 2 helps with the "every other" bit. 

String build =""
String x=jTextField1.getText();
x=x.toLowerCase();
int y=x.length();
for(int i=0;i<y;i++)
{
     if(i%2==0){
        build+=Character.toUpperCase(x.charAt(i));
     else{
        build+=x.charAt(i);
     }
}
x=build; //not necessary, you could just use build.

Happy oding! Leave a comment if you have any questions.

Upvotes: 0

davesbrain
davesbrain

Reputation: 606

@Test
public void alternateUppercase(){
    String testString = "This is a !!!!! test - of the emergency? broadcast System.";

    char[] arr = testString.toLowerCase().toCharArray();

    boolean makeUppercase = true;
    for (int i=0; i<arr.length; i++) {
        if(makeUppercase && Character.isLetter(arr[i])) {
            arr[i] = Character.toUpperCase(arr[i]);
            makeUppercase = false;
        } else if (!makeUppercase && Character.isLetter(arr[i])) {
            makeUppercase = true;
        }
    }
    String convertedString = String.valueOf(arr);
    System.out.println(convertedString);
}

Upvotes: 2

java.manish.2015
java.manish.2015

Reputation: 1071

public class PrintingStringInAlternativeCase {
    public static void main(String s[])
    {
        String testString = "TESTSTRING";
        String output = "";
        for (int i = 0; i < testString.length(); i++) {
            if(i%2 == 0)
            {
                output += Character.toUpperCase(testString.toCharArray()[i]);
            }else
            {
                output += Character.toLowerCase(testString.toCharArray()[i]);
            }
        }

        System.out.println("Newly generated string is as follow: "+ output);
    }
}

Upvotes: 0

bakoyaro
bakoyaro

Reputation: 2558

I'm sure there is a slicker way to do this, but this will work for a 2 minute-answer:

public String homeWork(){
        String x = "Hello World";
        StringBuilder sb = new StringBuilder();
        for(int i=0;i<=x.length();i++){
             char c = x.charAt(i);
             if(i%2==0){
                sb.append(String.valueOf(c).toUpperCase());
             } else {
                sb.append(String.valueOf(c).toLowerCase());
             }
        }
        return sb.toString();
    }

To explain i%2==0, if the remainder of i divided by 2 is equal to zero (even numbered) return true

Upvotes: 0

roeygol
roeygol

Reputation: 5048

you can make it using the 65 distnace of lower case and upper case ABCabc from the unicode table like:

String str = "abbfFDdshFSDjdFDSsfsSdoi".toLowerCase();

char c;
boolean state = false; 
String newStr = "";
for (int i=0; i<str.length(); i++){
    c = str.charAt(o);

    if (state){
         newStr += c;
    }
    else {
         newStr += c + 65;
    }
    state = !state;
}

Upvotes: 0

Elliott Frisch
Elliott Frisch

Reputation: 201497

First, java indexes start at 0 (not 1). I think you are asking for something as simple as alternating calls to Character.toLowerCase(char) and Character.toUpperCase(char) on the result of modulo (remainder of division) 2.

String x = jTextField1.getText();
for (int i = 0, len = x.length(); i < len; i++) {
    char ch = x.charAt(i);
    if (i % 2 == 0) {
        System.out.print(Character.toLowerCase(ch));
    } else {
        System.out.print(Character.toUpperCase(ch));
    }
}
System.out.println();

Upvotes: 1

Peter Lawrey
Peter Lawrey

Reputation: 533710

Strings start at index 0 and finish at index x.length()-1

To look up a String by index you can use String.charAt(i)

To convert a character to upper case you can do Character.toUpperCase(ch);

I suggest you build a StringBuilder from these characters which you can toString() when you are done.

Upvotes: 1

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