Reputation: 391
Assume I am getting the following java Exception
ERROR - Error occured while reading properties. (MyPropertyReader.java)
java.lang.NullPointerException
at com.x.MyPropertyReader.init(PropertyReader.java:**222**)
at com.x.MyPropertyReader.<init>(PropertyReader.java:119)
How do you find out , what excatly the code block looks like at line 222 ?
For example: The above exception is due to the following line of code and I want to see the much like below line in log files.
propertyConfiguration.getProperty("REPORT_INFLUENCE_THRESHOLD"))).trim());
I want to see REPORT_INFLUENCE_THRESHOLD
string in the log files.
However I am curious in general what how to programmatically print line in 222 during execution.
Upvotes: 2
Views: 183
Reputation: 121710
You first need, obviously, to have the source files in your classpath. This or at least at a location you know you can find them.
Then you would use Throwable
's .getStackTrace()
which returns an array of StackTraceElement
s.
The latter has the source file name and line (IF AVAILABLE; a jar may, or may not, have been compiled with debug information); from then on, read, find line, print!
Upvotes: 2