CODEWITHSUNDEEP
pythonlistpython-3.xlist-comprehension
Sven
Sven

Reputation: 153

Python 3.4: replace "0x" with "\x" in a List

Hi I want to replace "0x" with "\x" in this list:

['0x50', '0x0', '0x0', '0x0']

I tried it with this list comprehension:

result = ['0x50', '0x0', '0x0', '0x0']
result = [x.replace("0x","\x") for x in result]

But it gives me this Error:

(unicode error)"unicodeescape" codex cant decode byte in position 0-1: truncated \xXX escape

How can I change "0x" and "\x" now?

Upvotes: 0

Views: 1626

Answers (1)

Bhargav Rao
Bhargav Rao

Reputation: 52161

Make it a raw string as in

>>> l = ['0x50', '0x0', '0x0', '0x0']
>>> [i.replace('0x',r'\x') for i in l]
['\\x50', '\\x0', '\\x0', '\\x0']

Or double-escape \ as in

>>> [i.replace('0x','\\x') for i in l]
['\\x50', '\\x0', '\\x0', '\\x0']

Upvotes: 5

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