How to check validity of URL in Swift?

Question

Trying to make an app launch the default browser to a URL, but only if the URL entered is valid, otherwise it displays a message saying the URL is invalid.

How would I go about checking the validity using Swift?

Answer 1

Swift 5, a bit performant NSDataDetector approach (does quick return if string is empty)

extension String {

    var isValidURL: Bool {
        guard !isEmpty, !trimmingCharacters(in: .whitespacesAndNewlines).isEmpty else {
            return false
        }

        do {
            let detector = try NSDataDetector(types: NSTextCheckingResult.CheckingType.link.rawValue)
            let matches = detector.matches(in: self, 
                                           options: [],
                                           range: NSRange(location: .zero, length: utf16.count))
            return !matches.isEmpty
        } catch {
            return false
        }
    }
}

// Test
let urlString1 = "https://you.test.com/0003-example?param=value"
let urlString2 = "www.apple.com"
let urlString3 = "http://example.com"
let urlString4 = "ftp://ftp.example.com/file.txt"
let urlString5 = ""
let urlString6 = "  "

urlString1.isValidURL // true
urlString2.isValidURL // true
urlString3.isValidURL // true
urlString4.isValidURL // true
urlString5.isValidURL // false
urlString6.isValidURL // false

Answer 2

extension String {
  var isValidUrl: Bool {
    if let url = NSURL(string: self) {
      return UIApplication.shared.canOpenURL(url as URL)
    }
    return false
  }
}

Usage:

let test1 = "abc"
let isValidUrl = test1.isValidUrl

// Result of isValidUrl will be False


let test1 = "https://www.google.com/"
let isValidUrl = test1.isValidUrl

// Result of isValidUrl will be True

Answer 3

//Add in "extension String"
func verifyUrl()  -> Bool {
    var newString = self
    let index = self.index(self.startIndex, offsetBy: 4)
    let mySubstring = self.prefix(upTo: index)
    if mySubstring == "www." {
        newString = "https://" + newString
    }
    if let url = NSURL(string: newString) {
        return UIApplication.shared.canOpenURL(url as URL)
    }
    return false
}

Answer 4

Most of the answer here doesn't address my issue so I'm posting here how I resolved it:

static func isValidDomain(domain: String?) -> Bool {
    guard let domain = domain else {
        return false
    }
    // Modified version of https://stackoverflow.com/a/49072718/2304737
    let detector = try! NSDataDetector(types: NSTextCheckingResult.CheckingType.link.rawValue)
    let domainWithScheme = "https://\(domain)"
    if let url = URL(string: domainWithScheme),
       let match = detector.firstMatch(in: domainWithScheme, options: [], range: NSRange(location: 0, length: domainWithScheme.utf16.count)) {
        // it is a link, if the match covers the whole string
        return match.range.length == domainWithScheme.utf16.count && url.host != nil
    } else {
        return false
    }
}

What lacks on Milan Nosáľ's answer is, it doesn't address this particular input:

https://#view-?name=post&post.post_id=519&message.message_id=349

So I just add host check existence and unschemed "URL".

Answer 5

If your goal is to verify if your application can open a URL, here is what you can do. Although safari can open the URL, the website might not exist or it might be down.

// Swift 5
func verifyUrl (urlString: String?) -> Bool {
    if let urlString = urlString {
        if let url = NSURL(string: urlString) {
            return UIApplication.shared.canOpenURL(url as URL)
        }
    }
    return false
}

As a side note, this does not check whether or not a URL is valid or complete. For example, a call that passes "https://" returns true.

Answer 6

Swift 5.1 Solution

extension String {
    func canOpenUrl() -> Bool {
        guard let url = URL(string: self), UIApplication.shared.canOpenURL(url) else { return false }
        let regEx = "((https|http)://)((\\w|-)+)(([.]|[/])((\\w|-)+))+"
        let predicate = NSPredicate(format:"SELF MATCHES %@", argumentArray:[regEx])
        return predicate.evaluate(with: self)
    }
}

Answer 7

2020, I was tasked on fixing a bug of a method for underlining string links within a string. Most of the answers here don't work properly (try: aaa.com.bd or aaa.bd) These links should be valid. And then I stumbled upon the regex string for this.

Ref: https://urlregex.com/

So based on that regex

"((?:http|https)://)?(?:www\\.)?[\\w\\d\\-_]+\\.\\w{2,3}(\\.\\w{2})?(/(?<=/)(?:[\\w\\d\\-./_]+)?)?"

We can write a function.

SWIFT 5.x:

extension String {
    var validURL: Bool {
        get {
            let regEx = "((?:http|https)://)?(?:www\\.)?[\\w\\d\\-_]+\\.\\w{2,3}(\\.\\w{2})?(/(?<=/)(?:[\\w\\d\\-./_]+)?)?"
            let predicate = NSPredicate(format: "SELF MATCHES %@", argumentArray: [regEx])
            return predicate.evaluate(with: self)
        }
    }
}

OBJECTIVE-C (write this however you want, category or not).

- (BOOL)stringIsValidURL:(NSString *)string
{
    NSString *regEx = @"((?:http|https)://)?(?:www\\.)?[\\w\\d\\-_]+\\.\\w{2,3}(\\.\\w{2})?(/(?<=/)(?:[\\w\\d\\-./_]+)?)?";
    NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF MATCHES %@" argumentArray:@[regEx]];
    return [predicate evaluateWithObject:string];
}

Answer 8

Swift 4 elegant solution using NSDataDetector:

extension String {
    var isValidURL: Bool {
        let detector = try! NSDataDetector(types: NSTextCheckingResult.CheckingType.link.rawValue)
        if let match = detector.firstMatch(in: self, options: [], range: NSRange(location: 0, length: self.utf16.count)) {
            // it is a link, if the match covers the whole string
            return match.range.length == self.utf16.count
        } else {
            return false
        }
    }
}

Usage:

let string = "https://www.fs.blog/2017/02/naval-ravikant-reading-decision-making/"
if string.isValidURL {
    // TODO
}

Reasoning behind using NSDataDetector instead of UIApplication.shared.canOpenURL:

I needed a method that would detect whether the user provided an input that is an URL to something. In many cases, users don't include the http:// nor https:// URL scheme in the URL they type in - e.g., instead of "http://www.google.com" they would type in "www.google.com". Without the URL scheme, the UIApplication.shared.canOpenURL will fail to recognize the URL and will return false. NSDataDetector is, compared to UIApplication.shared.canOpenURL, a rather forgiving tool (as @AmitaiB mentioned in comments) - and it can detect even URLs without the http:// scheme. This way I am able to detect a URL without having to try to add the scheme everytime when testing the string.

Sidenote - SFSafariViewController can open only URLs with http:///https://. Thus, if a detected URL does not have a URL scheme specified, and you want to open the link, you will have to prepend the scheme manually.

Answer 9

This accepted answer doesn't work in my case with wrong url without data https://debug-cdn.checkit4team.com/5/image/Y29tbW9uL2RlZmF1bHRfYXZhdGFyLnBuZw==

So I write extension to solve

extension String {
    var verifyUrl: Bool {
        get {
            let url = URL(string: self)

            if url == nil || NSData(contentsOf: url!) == nil {
                return false
            } else {
                return true
            }
        }
    }
}

Use it:

if string. verifyUrl {
    // do something
}

Hope this help!

Answer 10

Version that works with Swift 4.2 and has reliable URL pattern matching ...

func matches(pattern: String) -> Bool
{
    do
    {
        let regex = try NSRegularExpression(pattern: pattern, options: [.caseInsensitive])
        return regex.firstMatch(in: self, options: [], range: NSRange(location: 0, length: utf16.count)) != nil
    }
    catch
    {
        return false
    }
}


func isValidURL() -> Bool
{
    guard let url = URL(string: self) else { return false }
    if !UIApplication.shared.canOpenURL(url) { return false }

    let urlPattern = "(http|ftp|https):\\/\\/([\\w+?\\.\\w+])+([a-zA-Z0-9\\~\\!\\@\\#\\$\\%\\^\\&\\*\\(\\)_\\-\\=\\+\\\\\\/\\?\\.\\:\\;\\'\\,]*)?"
    return self.matches(pattern: urlPattern)
}

Answer 11

Helium having to deal with various schemes:

struct UrlHelpers {
    // Prepends `http://` if scheme isn't `https?://` unless "file://"
    static func ensureScheme(_ urlString: String) -> String {
        if !(urlString.lowercased().hasPrefix("http://") || urlString.lowercased().hasPrefix("https://")) {
            return urlString.hasPrefix("file://") ? urlString : "http://" + urlString
        } else {
            return urlString
        }
    }

    // https://mathiasbynens.be/demo/url-regex
    static func isValid(urlString: String) -> Bool {
        // swiftlint:disable:next force_try
        if urlString.lowercased().hasPrefix("file:"), let url = URL.init(string: urlString) {
            return FileManager.default.fileExists(atPath:url.path)
        }

        let regex = try! NSRegularExpression(pattern: "^(https?://)[^\\s/$.?#].[^\\s]*$")
        return (regex.firstMatch(in: urlString, range: urlString.nsrange) != nil)
    }
}

Answer 12

Swift 4.2 Elegant URL construction with verification

import Foundation
import UIKit

extension URL {

  init?(withCheck string: String?) {
    let regEx = "((https|http)://)((\\w|-)+)(([.]|[/])((\\w|-)+))+"
    guard
        let urlString = string,
        let url = URL(string: urlString),
        NSPredicate(format: "SELF MATCHES %@", argumentArray: [regEx]).evaluate(with: urlString),
        UIApplication.shared.canOpenURL(url)
        else {
            return nil
    }

    self = url
  }
}

Usage

var imageUrl: URL? {
    if let url = URL(withCheck: imageString) {
        return url
    }
    if let url = URL(withCheck: image2String) {
        return url
    }
    return nil
}

Answer 13

I found this one clean (In Swift):

func canOpenURL(string: String?) -> Bool {
    guard let urlString = string else {return false}
    guard let url = NSURL(string: urlString) else {return false}
    if !UIApplication.sharedApplication().canOpenURL(url) {return false}

    //
    let regEx = "((https|http)://)((\\w|-)+)(([.]|[/])((\\w|-)+))+"
    let predicate = NSPredicate(format:"SELF MATCHES %@", argumentArray:[regEx])
    return predicate.evaluateWithObject(string)
}

Usage:

if canOpenURL("abc") {
    print("valid url.")
} else {
    print("invalid url.")
}

===

for Swift 4.1:

func canOpenURL(_ string: String?) -> Bool {
    guard let urlString = string,
        let url = URL(string: urlString)
        else { return false }

    if !UIApplication.shared.canOpenURL(url) { return false }

    let regEx = "((https|http)://)((\\w|-)+)(([.]|[/])((\\w|-)+))+"
    let predicate = NSPredicate(format:"SELF MATCHES %@", argumentArray:[regEx])
    return predicate.evaluate(with: string)
}

// Usage
if canOpenURL("abc") {
    print("valid url.")
} else {
    print("invalid url.") // This line executes
}

if canOpenURL("https://www.google.com") {
    print("valid url.") // This line executes
} else {
    print("invalid url.")
}

Answer 14

This will return a boolean for a URL's validity, or nil if an optional URL with a value of nil is passed.

extension URL {

    var isValid: Bool {
        get {
            return UIApplication.shared.canOpenURL(self)
        }
    }

}

Note that, if you plan to use a Safari view, you should test url.scheme == "http" || url.scheme == "https".

Answer 15

This is for latest Swift 4, based on Doug Amos answer (for swift 3)

public static func verifyUrl (urlString: String?) -> Bool {
    //Check for nil
    if let urlString = urlString {
        // create NSURL instance
        if let url = NSURL(string: urlString) {
            // check if your application can open the NSURL instance
            return UIApplication.shared.canOpenURL(url as URL)
        }
    }
    return false
}

Answer 16

For Swift 4 version

static func isValidUrl (urlString: String?) -> Bool {
    if let urlString = urlString {
        if let url = URL(string: urlString) {
            return UIApplication.shared.canOpenURL(url)
        }
    }
    return false
}

Answer 17

For swift 4 you can use:

class func verifyUrl (urlString: String?) -> Bool {
    //Check for nil
    if let urlString = urlString {
        // create NSURL instance
        if let url = URL(string: urlString) {
            // check if your application can open the NSURL instance
            return UIApplication.shared.canOpenURL(url)
        }
    }
    return false
}

Answer 18

In some cases it can be enough to check that the url satisfies RFC 1808. There are several ways to do this. One example:

if let url = URL(string: urlString), url.host != nil {
  // This is a correct url
}

This is because .host, as well as .path, .fragment and a few other methods would return nil if url doesn't conform to RFC 1808.

If you don't check, you might have this kind of messages in console log:

Task <DF46917D-1A04-4E76-B54E-876423224DF7>.<72> finished with error - code: -1002

Answer 19

Try this:

func isValid(urlString: String) -> Bool
{
    if let urlComponents = URLComponents.init(string: urlString), urlComponents.host != nil, urlComponents.url != nil
    {
        return true
    }
    return false
}

This simply checks for valid URL components and if the host and url components are not nil. Also, you can just add this to an extensions file

Answer 20

extension String {    
    func isStringLink() -> Bool {
        let types: NSTextCheckingResult.CheckingType = [.link]
        let detector = try? NSDataDetector(types: types.rawValue)
        guard (detector != nil && self.characters.count > 0) else { return false }
        if detector!.numberOfMatches(in: self, options: NSRegularExpression.MatchingOptions(rawValue: 0), range: NSMakeRange(0, self.characters.count)) > 0 {
            return true
        }
        return false
    }
}

//Usage
let testURL: String = "http://www.google.com"
if testURL.isStringLink() {
    //Valid!
} else {
    //Not valid.
}

It's advised to use this check only once and then reuse.

_{P.S. Credits to Shachar for this function.}

Answer 21

For a swift 3 version of the accepted answer:

func verifyUrl(urlString: String?) -> Bool {
    if let urlString = urlString {
        if let url = URL(string: urlString) {
            return UIApplication.shared.canOpenURL(url)
        }
    }
    return false
}

Or for a more Swifty solution:

func verifyUrl(urlString: String?) -> Bool {
    guard let urlString = urlString,
          let url = URL(string: urlString) else { 
        return false 
    }

    return UIApplication.shared.canOpenURL(url)
}

Answer 22

Using 'canOpenUrl' was too expensive for my use case, I found this approach to be quicker

func isStringLink(string: String) -> Bool {
    let types: NSTextCheckingResult.CheckingType = [.link]
    let detector = try? NSDataDetector(types: types.rawValue)
    guard (detector != nil && string.characters.count > 0) else { return false }
    if detector!.numberOfMatches(in: string, options: NSRegularExpression.MatchingOptions(rawValue: 0), range: NSMakeRange(0, string.characters.count)) > 0 {
        return true
    }
    return false
}

Answer 23

This isn't a regex approach, but it is a naive one that works well for making sure there is a host and an extension if you want a simple and inexpensive approach:

extension String {
    var isValidUrlNaive: Bool {
        var domain = self
        guard domain.count > 2 else {return false}
        guard domain.trim().split(" ").count == 1 else {return false}
        if self.containsString("?") {
            var parts = self.splitWithMax("?", maxSplit: 1)
            domain = parts[0]
        }
        return domain.split(".").count > 1
    }
}

Use this only if you want a quick way to check on the client side and you have server logic that will do a more rigorous check before saving the data.

Answer 24

My personal preference is to approach this with an extension, because I like to call the method directly on the string object.

extension String {

    private func matches(pattern: String) -> Bool {
        let regex = try! NSRegularExpression(
            pattern: pattern,
            options: [.caseInsensitive])
        return regex.firstMatch(
            in: self,
            options: [],
            range: NSRange(location: 0, length: utf16.count)) != nil
    }

    func isValidURL() -> Bool {
        guard let url = URL(string: self) else { return false }
        if !UIApplication.shared.canOpenURL(url) {
            return false
        }

        let urlPattern = "^(http|https|ftp)\\://([a-zA-Z0-9\\.\\-]+(\\:[a-zA-Z0-9\\.&%\\$\\-]+)*@)*((25[0-5]|2[0-4][0-9]|[0-1]{1}[0-9]{2}|[1-9]{1}[0-9]{1}|[1-9])\\.(25[0-5]|2[0-4][0-9]|[0-1]{1}[0-9]{2}|[1-9]{1}[0-9]{1}|[1-9]|0)\\.(25[0-5]|2[0-4][0-9]|[0-1]{1}[0-9]{2}|[1-9]{1}[0-9]{1}|[1-9]|0)\\.(25[0-5]|2[0-4][0-9]|[0-1]{1}[0-9]{2}|[1-9]{1}[0-9]{1}|[0-9])|localhost|([a-zA-Z0-9\\-]+\\.)*[a-zA-Z0-9\\-]+\\.(com|edu|gov|int|mil|net|org|biz|arpa|info|name|pro|aero|coop|museum|[a-zA-Z]{2}))(\\:[0-9]+)*(/($|[a-zA-Z0-9\\.\\,\\?\\'\\\\\\+&%\\$#\\=~_\\-]+))*$"
        return self.matches(pattern: urlPattern)
    }
}

This way it is also extensible with another use-cases, such as isValidEmail, isValidName or whatever your application requires.

Answer 25

var url:NSURL = NSURL(string: "tel://000000000000")!
if UIApplication.sharedApplication().canOpenURL(url) {
    UIApplication.sharedApplication().openURL(url)
} else {
     // Put your error handler code...
}

Answer 26

You can use the NSURL type (whose constructor returns an optional type) combined with an if-let statement to check the validity of a given URL. In other words, make use of the NSURL failable initializer, a key feature of Swift:

let stringWithPossibleURL: String = self.textField.text // Or another source of text

if let validURL: NSURL = NSURL(string: stringWithPossibleURL) {
    // Successfully constructed an NSURL; open it
    UIApplication.sharedApplication().openURL(validURL)
} else {
    // Initialization failed; alert the user
    let controller: UIAlertController = UIAlertController(title: "Invalid URL", message: "Please try again.", preferredStyle: .Alert)
    controller.addAction(UIAlertAction(title: "OK", style: .Default, handler: nil))

    self.presentViewController(controller, animated: true, completion: nil)
}