Reputation: 5985
I am trying to do something that I thought I've done 100 times already... I'm getting and making a new image after an ajax call and am trying to insert it into an appropriate, pre-existing div
The HTML looks like this
<div class="preload">
<div class="createYourOwn">...</div>
<img src="source.com"/>
<img src="source.com"/>
<img src="source.com"/>
<img src="source.com"/>
<img src="source.com"/>
</div?
The AJAX call does this:
$.post("script.php", {phone:phone}, function(data){
if(data){
var newImage = "<img src='https://api.twilio.com" + data + "/>";
$(newImage).insertAfter('.createYourOwn');
}
});
I've tried this as well:
$("<img src='https://api.twilio.com" + data + "/>").insertAfter('.createYourOwn');
And this:
$(newImage).append('.preload');
even though that doesn't have the desired outcome.
I'd like to insert the image that I receive with the data just after the .createYourOwn
div inside of .preload
.
Not sure what's going on. But nothing is happening, no errors, not even an image with a borked src
. Nothing at all happens.
Anyone have any ideas?
Thank you!
Upvotes: 0
Views: 752
Reputation: 85545
Concatenate string properly:
Replace this:
var newImage = "<img src='https://api.twilio.com" + data + "/>";
// you're missing to close quote for src here ^^
With this:
var newImage = "<img src='https://api.twilio.com" + data + "' />";
Or switch the quotes:
var newImage = '<img src="https://api.twilio.com' + data + '" />';
Upvotes: 3