CODEWITHSUNDEEP
pythonparsingdictionaryreplace
Annamarie
Annamarie

Reputation: 313

Python: parsing a value(string) in a dictionary and replace it

my dictionary:

mydict{'a':'/1/2/3/4/5/wrong1', 'b':'/x/y/x/u/t/wrong2'}

I would like parse the value, and replace 'wrong*' with 'right'. 'Right' is always the same, whereas 'wrong' is different each time.

'wrong' looks e.g. like that: folder_x/folder_y/somelongfilename.gz

'right' looks like that: *-AAA/debug.out

so afterwards my dictionary should look like that:

mydict{'a':'/1/2/3/4/5/right', 'b':'/x/y/x/u/right'}

Just replacing the value won't work here because I want to parse the value and replace only the last part of it. It is important to keep the first part of the value.

Does anyone have an idea how to solve this.

Thank you.

Upvotes: 0

Views: 541

Answers (1)

Cory Kramer
Cory Kramer

Reputation: 118021

You could use a re.sub to handle the replacement for you

>>> import re
>>> {k : re.sub('wrong', 'right', v) for k,v in mydict.items()}
{'b': '/x/y/x/u/t/right2',
 'a': '/1/2/3/4/5/right1'}

Upvotes: 1

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