CODEWITHSUNDEEP
bash
齐天大圣
齐天大圣

Reputation: 1189

Bash script, find all the files in current folder that contains specific string

so i have a line of code like:

list=$(find . -maxdepth 1 -name "$1" -print0 | sed 's,\.\/,,g')
echo $list

so in terminal when i do bash script_name string

i hope it will display all the files that contain "string"

Now in a folder i have 4 matches : TesT1.c TesT1.h TesT2.c TesT2.h

when i do 

bash script_name TesT*

my code only return the first match ,which is TesT1.c

Where did i do wrong, thank you in advance

Upvotes: 0

Views: 216

Answers (2)

Etan Reisner
Etan Reisner

Reputation: 81032

When you run bash script_name TesT* your current shell expands the glob so your run command is actually bash script_name TesT1.c TesT1.h TesT2.c TesT2.h.

Your script then uses $1 (the first argument) and runs

find . -maxdepth 1 -name "TesT1.c" -print0 | sed 's,\.\/,,g'

which obviously only finds itself.

Quote the glob on the initial command line.

bash script_name 'TesT*'

Also there's no reason to stuff the output from find into a variable and then echo it back out like that.

Upvotes: 0

anubhava
anubhava

Reputation: 786001

When you do:

bash script_name TesT*

bash expands TesT* at the time of calling your script and makes it:

bash script_name TesT1.c TesT1.h TesT2.c TesT2.h

Since you're only using $1 you just get: TesT1.c

You need to call you script as

bash script_name 'TesT*'

to avoid expansion of glob pattern (due to use of single quote)

Upvotes: 1

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