CODEWITHSUNDEEP
pythonmacosansible
George Armhold
George Armhold

Reputation: 31064

ansible can't find pycurl on OSX

I'm just getting started with ansible, and I'm trying to get it to work with the linode module from OSX Yosemite. I'm using brew-installed Python, and pip-installed ansible. So I have done the following:

$ brew install python
$ PYCURL_SSL_LIBRARY=nss pip install pycurl
$ CFLAGS=-Qunused-arguments CPPFLAGS=-Qunused-arguments pip install ansible

To test:

$ which python
/usr/local/bin/python

$ python --version
Python 2.7.9

$ which ansible
/usr/local/bin/ansible

$ ansible --version
ansible 1.8.2
   configured module search path = None

When I run my playbook I get:

failed=True msg='pycurl required for this module'

So somehow ansible is not seeing the pycurl library.

Here is the playbook:

---
- hosts: 127.0.0.1
  connection: local
  gather_facts: no

  tasks:
  - name: "provision a server"
    local_action:
      module: linode
      api_key: FOO
      name: linode-test1
      plan: 1
      datacenter: 1
      distribution: 99
      password: 'superSecureRootPassword'
      ssh_pub_key: ssh-rsa FOO
      swap: 768
      wait: yes
      wait_timeout: 600
      state: present

Upvotes: 1

Views: 1095

Answers (2)

William Turrell
William Turrell

Reputation: 3326

I was able to fix this on OS X El Capitan 10.11.6 by editing hosts:

[local]
localhost ansible_python_interpreter=/usr/local/bin/python

You may then need additional Python dependencies:

pip install pycurl
pip install linode-python

Upvotes: 0

NIlesh Sharma
NIlesh Sharma

Reputation: 5655

It's happening on ubuntu as well, finally figured out the solution. You need to explicity pass path to python executable

Change Ansible hosts file from 

[local]
localhost

to

[local]
localhost ansible_python_interpreter=/usr/local/bin/python

or to your virtual environment python path.

Upvotes: 1

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