Reputation: 1865
I have my code below that consits of a structure, a main, and a function. The function is supposed to display two parameters that have certain values, both of which point to the same structure.
The problem I dont know how to add the SECOND parameter onto the following code :
#include<stdio.h>
#define first 500
#define sec 500
struct trial{
int f;
int r;
float what[first][sec];
};
int trialtest(trial *test);
main(){
trial test;
trialtest(&test);
}
int trialtest(trial *test){
int z,x,i;
for(i=0;i<5;i++){
printf("%f,(*test).what[z][x]);
}
return 0;
}
I need to add a new parameter test_2
there (IN THE SAME FUNCTION) using this code :
for(i=0;i<5;i++){
printf("%f,(*test_2).what[z][x]);
How does int trialtest(trial *test)
changes ?
and how does it change in main ?
I know that I should declare test_2
as well, like this :
trial test,test_2;
But what about passing the address in the function ? I do not need to edit it right ?
trialtest(&test); --- This will remain the same ?
So please, tell me how would I use test_2 as a parameter pointing to the same structure as test, both in the same function..
Thank you !! Please tell me if you need more clarification
Upvotes: 0
Views: 223
Reputation: 12392
I think that this is your homework, so I'll just write a different function that may give you an idea of what (I think) you need to do. I read that you don't want to change the trail_test parameter list, so I stuck with a similar parameter list.
struct thing {
/* put some stuff here */
};
typedef struct thing thing; /* because this is C, not C++ */
int how_many_things(thing * thing_list);
int main(void) {
int i;
thing * a;
int count_init = random(); /* let's surprise ourselves and make a random number of these */
count_init %= 128; /* but not too many or it might not work at all */
a = malloc(count_init*sizeof(things)+1);
for (i = 0; i < count_init; i++) {
thing_init(&(a[i]));
}
make_illegal_thing(&(a[count_init]) ); /* like '\0' at the end of a string */
printf("There are %i things in the list\n", how_many_things(a) );
return 0;
}
/* This is very similar to strlen */
int how_many_things(thing * a) {
int count = 0;
while (is_legal_thing(a) ) {
a++;
count++;
}
return count;
}
Upvotes: 1