Reputation:
The following program prints 42:
#include <iostream>
struct A
{
operator int(){ return 42; }
};
struct B
{
operator A(){ return A(); }
};
B b;
int a = A(b);
int main(){ std::cout << a << std::endl; } //42
But if we try to define cope/move or both contructors it won't work.
#include <iostream>
struct A
{
A(A&&){ std::cout << "A(A&&)" << std::endl; }
A(A&){ std::cout << "A(A&)" << std::endl; }
operator int(){ return 42; }
};
struct B
{
operator A(){ return A(); }
};
B b;
int a = A(b);
int main(){ std::cout << a << std::endl; } //Error
I thought, the relevant section, describing that behavior is N4296::8.5/17.7 [dcl.init]
If the destination type is a (possibly cv-qualified) class type:
[...]
— Otherwise, if the source type is a (possibly cv-qualified) class type, conversion functions are considered. The applicable conversion functions are enumerated (13.3.1.5), and the best one is chosen through overload resolution (13.3). The user-defined conversion so selected is called to convert the initializer expression into the object being initialized. If the conversion cannot be done or is ambiguous, the initialization is ill-formed.
It shouldn't depends on absence/presence of the constructors. We just should have to have appropriate conversion functions so as to choose the conversion sequence.
Upvotes: 0
Views: 53
Reputation: 302748
You effectively deleted the default constructor. From the standard (12.1/4, emphasis mine):
A default constructor for a class
X
is a constructor of classX
that can be called without an argument. If there is no user-declared constructor for classX
, a constructor having no parameters is implicitly declared as defaulted
IF there is no user-declared constructor. But you declared two, so there is no implicit default constructor. Thus, this:
operator A(){ return A(); }
// ^^^
can't compile. That's why the error you get is
error: no matching function for call to
A::A()
The code tries to call your conversion operator - but the body isn't valid.
Upvotes: 1