Reputation: 747
I'm studying C++ by 2 months and I'm having some problem with understanding the try-catch block in C++. I'm using the book : programming principles and practice using C++, here is what my book says :
the basic idea of the exceptions is that if a function find is an error that it cannot handle, it does not return normally, instead, it throws an exception indicating what went wrong. Any direct or indirect caller can catch the exception, that is, specify what to do if the called code used throw.
What does "any direct or indirect caller can cacht the exception means ? does the author means the caller of a function or the catch function ?". I'm confused about this, Could you exaplain it to me in simple way ?
Upvotes: 1
Views: 138
Reputation: 5291
Example for indirect call: Here the exception happens in the called function. But the try catch is placed in the calling function, and not the called function.
#include <iostream>
#include <exception>
using namespace std;
void divideByZero(){
int a = 5;
int b = a / 0;
throw(b);
}
int main()
{
try{
divideByZero();
}
catch (exception& e){
cout<<e.what()<<endl;
}
return 0;
}
Example for direct exception: Here the exception happens in the functions itself directly, and handled there itself.
#include <iostream>
using namespace std;
int main()
{
try{
int a = 5;
int b = a / 0;
throw(b);
}
catch (exception& e){
cout<<e.what()<<endl;
}
return 0;
}
The above program is used only for illustration and not for any real example, which you are likely to come across when you write a useful program.
Upvotes: 3