CODEWITHSUNDEEP
phpregexstringimagepreg-match-all
davidmarko
davidmarko

Reputation: 343

PHP Regex getting the last directory without file (or/and) parameters

Title is pretty much self explanatory but just to be more clear...

I want that all those 5 option :

http://www.example.com/directory1/directory2/?q=this/that/other
http://www.example.com/directory1/directory2/file.html
http://www.example.com/directory1/directory2/file.html?q=sometext
http://www.example.com/directory1/directory2/
http://www.example.com/directory1/directory2/?q=sometext

will return:

http://www.example.com/directory1/directory2/

So in other words...

Find the LAST ? (if exists) and THEN find the LAST / and ignore anything afterwards (no need to capture everything afterwards)

preg_match_all('/<a(.*?)href={HOW DO I SAY FIND THE **LAST ** /FROM THAT LINK, KEEP IT AND IGNORE EVERYTHING AFTERWARDS }>/s',$content,$images);

Upvotes: 1

Views: 217

Answers (4)

shivanshu patel
shivanshu patel

Reputation: 778

Try to use parse_url

which returns host, path and query separate.

// you can write something like
$url = parse_url($url);
$path = explode('/',$url['path']);
$lastDir = end($path);

Upvotes: 0

AbraCadaver
AbraCadaver

Reputation: 78994

Regex is great but use the proper tool for the job:

$parts  = parse_url($url);
$result = $parts['scheme'].$parts['host'].$parts['path'];

You can use dirname() on the path if needed. Also notice there are other components that you may want such as port, etc...

Upvotes: 0

SBH
SBH

Reputation: 1908

Use

preg_match_all('~[^\?]*/~', $str, $match);

to get everything without parts following ?.

Upvotes: 1

magon
magon

Reputation: 81

You can do something like that :

$uri = "http://www.example.com/directory1/directory2/file.html";
$pos = strrpos($uri, "/");
$shortUri = substr(uri, 0, $pos);

Upvotes: 1

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