CODEWITHSUNDEEP
python-3.x
Ashmoreinc
Ashmoreinc

Reputation: 122

How to make it change char after "b"

I'm trying to make a brute force type program and it gets too "b" and then just loops "b", i sort of have an idea on what is wrong but not how to fix it Here is my current code

target = input("What is the target word for you to get?\n")

chars = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z", "0", "1", "2", "3", "3", "4", "5", "6", "7", "8", "9"]
currPos = int()

attempt = chars[currPos]
nxt = currPos + 1

while(attempt != target):
    print (attempt)
    attempt = chars[nxt]
    currPos += 1
    currPos = int(0)

print("Success! \""+ attempt + "\" was the correct password correct!")

I know that i am going to have to change the while loop to probably a for loop maybe even containing a while loop. I'm not to sure

Upvotes: 0

Views: 38

Answers (1)

cwallach
cwallach

Reputation: 26

currPos = int(0) is incorrect. Simpler to replace the loop with

for attempt in chars :
    print(attempt)

Upvotes: 1

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