CODEWITHSUNDEEP
phparraysimplode
RK.
RK.

Reputation: 981

Implode an array without first element

I have an array like this:

[0]=>array( [cname] => ABC
            [12] => 60.7500
            [13] => 33.7500
            [14] => 47.7500
            [15] => 86.0000
            [16] => 62.2500
            [17] => 59.5000
            [18] => 78.0000
            [19] => 42.7500
            [20] => 36.0000
            [21] => 40.0000
            [22] => 40.0000
            [23] => 24.0000
    )
)

Now, I have to print the cname in one field and in next field I have to print its data using implode function. It works fine. But When I implode it, it also gives the company name as well, which I do not want.

Desired Result:

Name: ABC
Data: 60.7500, 33.7500, 47.7500 ....

How can I skip the first element using implode?

Upvotes: 11

Views: 10022

Answers (4)

CasualBen
CasualBen

Reputation: 909

Since not all viewers are reading the comments, here the best answer for me from @darren:

implode(', ', array_slice($array, 1))

Upvotes: 5

user2357023
user2357023

Reputation:

Try the following:

$removedElementValue = array_shift($yourArray);
$implodedArray = implode(',', $yourArray);

Upvotes: 3

Alexis King
Alexis King

Reputation: 43852

Just copy the array, then delete the cname property before calling implode.

$copy = $arr;
unset($copy['cname']);
implode($copy);

This works because in PHP, array assignment copies. (Sort of bizarre, but it works.)

Upvotes: 15

web-nomad
web-nomad

Reputation: 6003

Use array_shift followed by implode.

$array = YOUR_ORIGINAL_ARRAY;

$cname = array_shift($array);
$string = implode(',', $array);

Upvotes: 6

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