Reputation: 43
For an example I have MySQL table like:
id category date value
1 a 2013-01-02 7
2 a 2013-01-01 2
3 a 2013-01-01 3
4 b 2013-01-01 1
5 b 2013-01-02 4
6 b 2013-01-03 5
7 c 2013-01-03 4
8 c 2013-01-03 8
I need select records with MAX(date) for each category, but if date is the same, with MAX(id). So, expected result must be:
id category date value
1 a 2013-01-02 7
6 b 2013-01-03 5
8 c 2013-01-03 8
As you can see, dates for same category can be not sorted (like id=4,5).
I tried query like:
SELECT * FROM mytable t1
INNER JOIN
(
SELECT category, MAX(date) AS MAXDATE
FROM mytable
GROUP BY category
) t2
ON t1.category = t2.category
AND t1.date = t2.MAXDATE
It works fine, when we have no same dates in table. But for my case, it will return records with lowest ids:
id category date value
1 a 2013-01-01 7
6 b 2013-01-03 5
7 c 2013-01-03 4
Upvotes: 4
Views: 6314
Reputation: 1180
You are on the right track but you need to change your join. I think what you want is the following:
SELECT * FROM mytable t1
INNER JOIN
(
SELECT MAX(id) AS ID, MAX(date) AS MAXDATE
FROM mytable
GROUP BY category
) t2
ON t1.id = t2.ID
AND t1.date = t2.MAXDATE
As mentioned, the previous wont work for every use case. The following might.
SELECT a.*
FROM mytable AS a,
(
SELECT category, date, MAX(id) AS ID
FROM mytable
GROUP BY category, date
) AS b,
(
SELECT category, MAX(date) AS date
FROM mytable
GROUP BY category
) AS c
WHERE b.category = c.category
AND b.date = c.date
AND a.id = b.id
Upvotes: 4