CODEWITHSUNDEEP
cmatrix
Lolapanza
Lolapanza

Reputation: 51

Calculating sum of rows in matrix

The sum of rows part just doesn't work properly . Any suggestions? Also if the main diagonal is i==j, what will be the opposite diagonal ? How do i define it? 

int main (void) {
    int A[5][5];       
    int B[5];
    int x=0,sum=0;
    int n,m,i=0,j;

    printf("Enter rows and columns : \n");
    scanf("%d %d",&n,&m);
    printf("Enter matrix : \n");

    for (i = 0 ; i < n ; i++) {               
        for (j = 0 ; j < m ; j++) {
            scanf("%d",&A[i][j]);
        }
    }

    /* Sum of rows Problem */
    for(i = 0 ; i < n ; i++) {
        B[i] = 0;         
        for(j = 0 ; j < m ; j++) {
            B[i] = B[i] + A[i][j];
            ++i;        
        }
    }
    for(i = 0 ; i < n ; i++) {                        
        for(j = 0 ; j < m ; j++) {        
            printf("The sum of rows %d \n", B[j]);
        }
    }      
    return 0;
}

Upvotes: 1

Views: 129

Answers (1)

shauryachats
shauryachats

Reputation: 10385

Actually, you just have to remove ++i inside the inner loop, and the program runs fine.

Code:

int main (void) {
    int A[5][5];       
    int B[5];
    int x=0,sum=0;
    int n,m,i=0,j;

    printf("Enter rows and columns : \n");
    scanf("%d %d",&n,&m);
    printf("Enter matrix : \n");

    for (i = 0 ; i < n ; i++) {               
        for (j = 0 ; j < m ; j++) {
            scanf("%d",&A[i][j]);
        }
    }

    /* Sum of rows Problem */
    for(i = 0 ; i < n ; i++) {
        B[i] = 0;         
        for(j = 0 ; j < m ; j++) {
            B[i] = B[i] + A[i][j];    //Removed the stray ++i from here.   
        }
    }
    for(i = 0 ; i < n ; i++)
    {                                
            printf("The sum of row %d is %d \n",i+1,B[i]);
    }      
    return 0;
}

And answering your second question, the opposite diagonal is i == size - j- 1 if size is the size of the array.

Upvotes: 2

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