Reputation: 666
Am working on the table, my aim is to display rows orderly based on its sum of columns. I mean, highest valued rows should be displayed first and then, second highest values, then, go on.. Have tried and could not make it. Just give me an idea, and that is good enough for me. Am not able to come to any idea on how to reshuffle the rows based on its sum values. Any idea on this?
<div id="na_1" style="border: 1px solid gray;width: 450px;padding:10px;">
<form>
<input type="radio" value="All" onclick="Turnthis();"/>All
<input type="radio" value="Top15" onclick="TurnOutthis();"/>Top5
</form>
<table id="bt_01" border="1" width="100%">
<thead>
<tr><td>head1</td><td>head2</td><td>head3</td><td>head4</td><td>head5</td><td>head6</td><td>head7</td></tr>
</thead>
<tbody>
<tr><td>Subject1</td><td>501</td><td>501</td><td>501</td><td>550</td><td>560</td><td>570</td></tr>
<tr><td>Subject2</td><td>620</td><td>640</td><td>605</td><td>650</td><td>600</td><td>604</td></tr>
<tr><td>Subject3</td><td>730</td><td>730</td><td>740</td><td>750</td><td>760</td><td>790</td></tr>
<tr><td>Subject4</td><td>700</td><td>701</td><td>700</td><td>702</td><td>700</td><td>703</td></tr>
<tr><td>Subject5</td><td>220</td><td>201</td><td>202</td><td>222</td><td>210</td><td>203</td></tr>
<tr><td>Subject6</td><td>200</td><td>201</td><td>200</td><td>202</td><td>200</td><td>203</td></tr>
<tr><td>Subject7</td><td>200</td><td>201</td><td>200</td><td>202</td><td>200</td><td>203</td></tr>
<tr><td>Subject8</td><td>200</td><td>201</td><td>200</td><td>202</td><td>200</td><td>203</td></tr>
<tr><td>Total</td><td>202</td><td>201</td><td>200</td><td>202</td><td>200</td><td>203</td></tr>
</tbody>
</table>
</div>
After I pressed the 'Top5' button, then, the table should be displayed as follows[sample]
<div id="na_1" style="border: 1px solid gray;width: 450px;padding:10px;">
<form>
<input type="radio" value="All" onclick="Turnthis();"/>All
<input type="radio" value="Top15" onclick="TurnOutthis();"/>Top5
</form>
<table id="bt_01" border="1" width="100%">
<thead>
<tr><td>head1</td><td>head2</td><td>head3</td><td>head4</td><td>head5</td><td>head6</td><td>head7</td></tr>
</thead>
<tbody>
<tr><td>Subject3</td><td>730</td><td>730</td><td>740</td><td>750</td><td>760</td><td>790</td></tr>
<tr><td>Subject4</td><td>700</td><td>701</td><td>700</td><td>702</td><td>700</td><td>703</td></tr>
<tr><td>Subject2</td><td>620</td><td>640</td><td>605</td><td>650</td><td>600</td><td>604</td></tr>
<tr><td>Subject1</td><td>501</td><td>501</td><td>501</td><td>550</td><td>560</td><td>570</td></tr>
<tr><td>Subject5</td><td>220</td><td>201</td><td>202</td><td>222</td><td>210</td><td>203</td></tr>
</tbody>
</table></div>
Hope this makes sense. For your kind information, i except code only in javascript not in jquery.
Upvotes: 0
Views: 94
Reputation: 9076
I assume you want the "total" row at the end of the table after sort.Otherwise code can be 10-12 lines shorter.
i come up with this solution.I've commented out every portion for convenience .With a little help form getElementsByTagName,removeChild,createElement,and appendChild methods you can achieve what you are trying to do.It is really simple.I advice you go through it.The main thing is create an array of objects which hold three properties.And the properties are the actual tr element,its sum and the first td element which holds subject1,2,3....and Total string.Then sort them down with Array.prototype.sort() then add them serially to your tbody element
var radio=document.getElementById('radio');
if(radio.checked == true){ //check for radio element is checked or not
radio.checked=false;
}
var table=document.getElementById('bt_01');
var serialTdArr=[]; //array which will hold the array of objects
var storageForTotal='';// store the tr element that has 'Total' as value of its first td element
function Turnthis(e){
var tbody=document.getElementsByTagName('tbody')[0]; //get the current tbody element
var tr=tbody.getElementsByTagName('tr'); //get all tr elements inside tbody
for(i=0;i<tr.length;i++){ // loop over the tr elements
var sum=0;
var td=tr[i].getElementsByTagName('td'); //get all td element inside every tr element
for(j=1;j<td.length;j++){
sum+=parseInt(td[j].innerHTML); // sum them up
}
var firstTd=td[0].innerHTML; //save every subject1,subject2,3,...and Total string to a seperate variable
serialTdArr.push({index:tr[i],sum:sum,pointer:firstTd}); // an object which holds the tr element,its sum and its first td element value is pushed inside serialTdArr
}
var sortedArr=serialTdArr.sort(function(a,b){ // sort them down from higher to lower
if(a.sum < b.sum){
return 1;
}
if(a.sum > b.sum){
return -1;
}
return 0;
});
table.removeChild(tbody); // remove the current tbody
var newTbody=document.createElement('tbody'); // create a new tbody
table.appendChild(newTbody); // append it to table
for(i=0;i<sortedArr.length;i++){
if((sortedArr[i].pointer) != 'Total'){ // if it has no "Total" string then add them to tbody
newTbody.appendChild(sortedArr[i].index); // add to tbody
}else{
storageForTotal=sortedArr[i].index; // 'Total' row will be seperated and stored in a variable to be added later at the end of the table
}
}
newTbody.appendChild(storageForTotal); // add the tr which 'Total' to the last of td element
}
<div id="na_1" style="border: 1px solid gray;width: 450px;padding:10px;">
<form>
<input type="radio" id='radio' value="Sort Them All" onchange="Turnthis();"/>Sort Them All
</form>
<table id="bt_01" border="1" width="100%">
<thead>
<tr><td>head1</td><td>head2</td><td>head3</td><td>head4</td><td>head5</td><td>head6</td><td>head7</td></tr>
</thead>
<tbody>
<tr><td>Subject1</td><td>501</td><td>501</td><td>501</td><td>550</td><td>560</td><td>570</td></tr>
<tr><td>Subject2</td><td>620</td><td>640</td><td>605</td><td>650</td><td>600</td><td>604</td></tr>
<tr><td>Subject3</td><td>730</td><td>730</td><td>740</td><td>750</td><td>760</td><td>790</td></tr>
<tr><td>Subject4</td><td>700</td><td>701</td><td>700</td><td>702</td><td>700</td><td>703</td></tr>
<tr><td>Subject5</td><td>220</td><td>201</td><td>202</td><td>222</td><td>210</td><td>203</td></tr>
<tr><td>Subject6</td><td>200</td><td>201</td><td>200</td><td>202</td><td>200</td><td>203</td></tr>
<tr><td>Subject7</td><td>200</td><td>201</td><td>200</td><td>202</td><td>200</td><td>203</td></tr>
<tr><td>Subject8</td><td>200</td><td>201</td><td>200</td><td>202</td><td>200</td><td>203</td></tr>
<tr><td>Total</td><td>202</td><td>201</td><td>200</td><td>202</td><td>200</td><td>203</td></tr>
</tbody>
Upvotes: 0
Reputation: 147453
The trick is to get the rows you want and put them into an array, then sort the array and put the rows into the table in the right order. The following will sort the rows based on the cell values, so if the first cell value is equal, it uses the second, and so on. The sort may not be stable since it just uses the built–in Array.prototype.sort. If you want to to be stable, that is pretty simple (but generally not required).
Firstly, get the relevant tBody element and rows:
var tBody = document.getElementById('bt_01').tBodies[0];
var rows = tBody.rows;
rows is a live collection so you want to build an array form it (also helps with sorting). The following works fine in modern browsers:
var rowArr = Array.prototype.slice.call(rows);
But will not work in IE 8 and lower, you'll need to use a for loop (just one extra line of code):
var rowArr = [];
for (var i=0, iLen=rows.length; i<iLen; i++) rowArr[i] = rows[i];
To keep the last row as the last, just keep a reference:
var lastRow = rowArr[rowArr.length - 1];
Now sort based on the cell values from the second cell onward:
rowArr.sort(function(a, b) {
var aVal, bVal;
for (var i = 1, iLen = a.cells.length; i<iLen; i++) {
aVal = a.cells[i].textContent || a.cells[i].innerText;
bVal = b.cells[i].textContent || b.cells[i].innerText;
if (aVal != bVal) return aVal - bVal;
}
return 0;
});
Now put the rows into order:
for (var j=0, jLen=rowArr.length; j<jLen; j++) {
tBody.appendChild(rowArr[j]);
}
and finally, put the bottom row back at the bottom:
tBody.appendChild(lastRow);
and you're done. And it's shorter than the offered jQuery alternative (and likely a lot faster). ;-)
It would be best to put footer row in separate tFoot section as you've done with the header.
If you want to sort based on the sum of the values in each row, the sort part becomes:
rowArr.sort(function(a, b) {
var aSum = 0, bSum = 0;
for (var i = 1, iLen = a.cells.length; i<iLen; i++) {
aSum += parseFloat(a.cells[i].textContent || a.cells[i].innerText);
bSum += parseFloat(b.cells[i].textContent || b.cells[i].innerText);
}
return aSum - bSum;
});
Upvotes: 1
Reputation: 26888
This code works and tested on Chrome 30
Non-jQuery version (updated question):
<html>
<body>
<div id="na_1" style="border: 1px solid gray;width: 450px;padding:10px;">
<table id="bt_01" border="1" width="100%">
<thead>
<tr><td>head1</td><td>head2</td><td>head3</td><td>head4</td><td>head5</td><td>head6</td><td>head7</td></tr>
</thead>
<tbody>
<tr><td>Subject1</td><td>501</td><td>501</td><td>501</td><td>550</td><td>560</td><td>570</td></tr>
<tr><td>Subject2</td><td>620</td><td>640</td><td>605</td><td>650</td><td>600</td><td>604</td></tr>
<tr><td>Subject3</td><td>730</td><td>730</td><td>740</td><td>750</td><td>760</td><td>790</td></tr>
<tr><td>Subject4</td><td>700</td><td>701</td><td>700</td><td>702</td><td>700</td><td>703</td></tr>
<tr><td>Subject5</td><td>220</td><td>201</td><td>202</td><td>222</td><td>210</td><td>203</td></tr>
<tr><td>Subject6</td><td>200</td><td>201</td><td>200</td><td>202</td><td>200</td><td>203</td></tr>
<tr><td>Subject7</td><td>200</td><td>201</td><td>200</td><td>202</td><td>200</td><td>203</td></tr>
<tr><td>Subject8</td><td>200</td><td>201</td><td>200</td><td>202</td><td>200</td><td>203</td></tr>
</tbody>
<tfoot>
<tr><td>Total</td><td>202</td><td>201</td><td>200</td><td>202</td><td>200</td><td>203</td></tr>
</tfoot>
</table>
</div>
<input type='button' onclick='sort()' value='sort by sum' />
<script>
function sort() {
var t = document.getElementById('bt_01').children[1]; // tbody
var arr = [];
// find all tr
var trs = t.children;
for(;trs.length;) {
var tr = trs[0];
// find all td and calculate the sum
var sum = 0;
var tds = tr.children;
for(var y in tds) {
var td = tds[y];
var v = +td.textContent;
if (!isNaN(v)) sum += v;
};
// move them to arr
tr = tr.parentNode.removeChild(tr)
arr.push({sum: sum,tr: tr});
};
// sort it
arr.sort(function(a, b) {
if (a.sum < b.sum) return 1;
if (a.sum > b.sum) return -1;
return 0;
});
// attach back the tr in order
for (var z in arr) t.appendChild(arr[z].tr)
}
</script>
</body>
</html>
jQuery version:
<html>
<body>
<script src="http://code.jquery.com/jquery-1.11.2.min.js"></script>
<div id="na_1" style="border: 1px solid gray;width: 450px;padding:10px;">
<table id="bt_01" border="1" width="100%">
<thead>
<tr><td>head1</td><td>head2</td><td>head3</td><td>head4</td><td>head5</td><td>head6</td><td>head7</td></tr>
</thead>
<tbody>
<tr><td>Subject1</td><td>501</td><td>501</td><td>501</td><td>550</td><td>560</td><td>570</td></tr>
<tr><td>Subject2</td><td>620</td><td>640</td><td>605</td><td>650</td><td>600</td><td>604</td></tr>
<tr><td>Subject3</td><td>730</td><td>730</td><td>740</td><td>750</td><td>760</td><td>790</td></tr>
<tr><td>Subject4</td><td>700</td><td>701</td><td>700</td><td>702</td><td>700</td><td>703</td></tr>
<tr><td>Subject5</td><td>220</td><td>201</td><td>202</td><td>222</td><td>210</td><td>203</td></tr>
<tr><td>Subject6</td><td>200</td><td>201</td><td>200</td><td>202</td><td>200</td><td>203</td></tr>
<tr><td>Subject7</td><td>200</td><td>201</td><td>200</td><td>202</td><td>200</td><td>203</td></tr>
<tr><td>Subject8</td><td>200</td><td>201</td><td>200</td><td>202</td><td>200</td><td>203</td></tr>
</tbody>
<tfoot>
<tr><td>Total</td><td>202</td><td>201</td><td>200</td><td>202</td><td>200</td><td>203</td></tr>
</tfoot>
</table>
</div>
<input type='button' onclick='sort()' value='sort by sum' />
<script>
function sort() {
var t = $('#bt_01').find('tbody');
var arr = [];
// find all tr
t.find('tr').each(function(idx, tr) {
tr = $(tr);
// find all td and calculate the sum
var sum = 0;
tr.find('td').each(function(idx, td) {
td = $(td);
var v = +td.text();
if (!isNaN(v)) sum += v;
});
// move them to arr
arr.push({sum: sum,tr: tr.detach()});
});
// sort it
arr.sort(function(a, b) {
if (a.sum < b.sum) return 1;
if (a.sum > b.sum) return -1;
return 0;
});
// attach back the tr in order
for (var z in arr) t.append(arr[z].tr)
}
</script>
</body>
</html>
Upvotes: 0