CODEWITHSUNDEEP
javascriptfunctionobject
WhiteFloater
WhiteFloater

Reputation: 137

Javascript calling other object method

I have these two objects: A and B. I want to call A.something from B, but is not working...

A = function()
{
  function something()
  {
     //do something
  }
}

B = function()
{
  A.something();
}

this throws "typeError, A.something(); is not a function"...

Upvotes: 0

Views: 54

Answers (3)

Davin Tryon
Davin Tryon

Reputation: 67296

Your current code attempts to use A as an object when it is a function. You would need to invoke the function A(), but then its something method would still not be available (because it is not exposed).

If you want A to be an object, you could use an object literal like this:

A = {
  something: function()
  {
     //do something
  }
}

B = function()
{
  A.something();
}

Or for a more classical looking approach you could use new:

function A()
{
  this.something()
  {
     //do something
  }
}

B = function()
{
  var a = new A();
  a.something();
}

There are more ways as well. You can use Object.create or use a more functional approach by returning an object inside the A function.

Upvotes: 1

RononDex
RononDex

Reputation: 4173

First of all, to create an object in javascript you have to define your class A like this (easy approach, not using prototyping):

A = function()
{ 
  return {
    something = function()
    {
       //do something
    }
  }
}

Then create your object by calling var object = A().

So your code should look like this in the end:

A = function()
{ 
  return {
    something = function()
    {
       //do something
    }
  }
}

B = function()
{
  var aObject = A();
  aObject.something();
}

Upvotes: 0

James Donnelly
James Donnelly

Reputation: 128771

Don't declare A as a function itself, declare it as an object:

A = {}

Then inside place something as your function:

A = {
    something: function() {
        //do something
    }
}

You will now be able to call A.something().

Upvotes: 0

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