CODEWITHSUNDEEP
javaregexstring
barbara
barbara

Reputation: 3201

Java quoted string parsing with regex

Suppose I have a string

123 --o 45 xyz 67 "abc def" " ghi jkl m" " " "" xy z

which I need to parse into an array of strings

["123", "--o", "45", "xyz", "67", "abc def", " ghi jkl m", " ", "", "xy", "z"]

My straight approach to split a string by spaces (split("\\s+")) isn't suitable because it separates a string by spaces and doesn't consider double quotes.

But I also need to separate elements which is quoted (" ghi jkl m", "abc def", and " ").

How can I modify my regular expression in method split to achieve my goal?

UPD

We also should consider the spaces.

=> [a, "s ", abc, "", "ad"sdsd"sdsd"]

"ad"sdsd"sdsd" is a sinle element.

Upvotes: 2

Views: 132

Answers (2)

alpha bravo
alpha bravo

Reputation: 7948

or use this pattern to capture what you want

("[^"]+"|\S+)

Demo

Upvotes: 0

Avinash Raj
Avinash Raj

Reputation: 174874

Split your input according to the below regex which uses a positive lookahead assertion.

String text = "123 --o 45 xyz 67 \"abc def\" \" ghi jkl m\" \" \" \"\" xy z";
String parts[] = text.split("\\s+(?=(?:\"[^\"]*\"|[^\"])*$)");
System.out.println(Arrays.toString(parts));

Output:

[123, --o, 45, xyz, 67, "abc def", " ghi jkl m", " ", "", xy, z]

Upvotes: 1

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