CODEWITHSUNDEEP
javaspringspring-mvc
Damien Gallagher
Damien Gallagher

Reputation: 991

Spring Rest - Posting Files

I have the following code which I use for posting a file to a service and it works fine. The only problem I have, is that I have to write a temporary file to get a FileSystemResource for posting the object with the restTemplate

Is there anyway I can adapt the following code so that I dont have to write a temporary file?

    public String postNewIcon2(Integer fileId, MultipartFile multiPartfile) {
    LOG.info("Entered postNewIcon");

    Map<String, Object> params = getParamsWithAppKey();
    params.put("fileId", fileId);

    String result = null;
    File tempFile = null;
    try {

        String originalFileNameAndExtension = multiPartfile.getOriginalFilename();

        String tempFileName = "c:\\temp\\image";
        String tempFileExtensionPlusDot = ".png";

        tempFile = File.createTempFile(tempFileName, tempFileExtensionPlusDot);
        multiPartfile.transferTo(tempFile);
        FileSystemResource fileSystemResource = new FileSystemResource(tempFile);

        // URL Parameters
        MultiValueMap<String, Object> parts = new LinkedMultiValueMap<String, Object>();
        parts.add("file", fileSystemResource);

        // Post
        result = restTemplate.postForObject(getFullURLAppKey(URL_POST_NEW_ICON), parts, String.class, params);

    } catch (RestClientException restClientException) {
        System.out.println(restClientException);
    } catch (IOException ioException) {
        System.out.println(ioException);
    } finally {
        if (tempFile != null) {
            boolean deleteTempFileResult = tempFile.delete();
            LOG.info("deleteTempFileResult: {}", deleteTempFileResult);
        }
    }
    return result;
}

Thank you

Upvotes: 4

Views: 9251

Answers (2)

Jake N
Jake N

Reputation: 84

MultipartFile needs to have some temp location. Please try this code, to get physical file:

private File getTempFile(MultipartFile attachment){
    CommonsMultipartFile commonsMultipartFile = (CommonsMultipartFile) attachment;
    DiskFileItem diskFileItem = (DiskFileItem) commonsMultipartFile.getFileItem();
    return diskFileItem.getStoreLocation();
}

Upvotes: 1

Damien Gallagher
Damien Gallagher

Reputation: 991

Answer with help with Kresimir Nesek and this link Sending Multipart File as POST parameters with RestTemplate requests

The following code did the trick - no need for a temporary file now

    MultiValueMap<String, Object> map = new LinkedMultiValueMap<String, Object>();
final String filename="somefile.txt";
map.add("name", filename);
map.add("filename", filename);
ByteArrayResource contentsAsResource = new ByteArrayResource(content.getBytes("UTF-8")){
            @Override
            public String getFilename(){
                return filename;
            }
        };
map.add("file", contentsAsResource);
String result = restTemplate.postForObject(urlForFacade, map, String.class);

Upvotes: 11

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