Reputation: 911
How to get response as json format(application/json) in yii?
Upvotes: 55
Views: 67116
Reputation: 193
for Yii2 use this simple to remember option
Yii::$app->response->format = "json";
return $data
Upvotes: 1
Reputation: 5269
Create this function in your (base) Controller:
/**
* Return data to browser as JSON and end application.
* @param array $data
*/
protected function renderJSON($data)
{
header('Content-type: application/json');
echo CJSON::encode($data);
foreach (Yii::app()->log->routes as $route) {
if($route instanceof CWebLogRoute) {
$route->enabled = false; // disable any weblogroutes
}
}
Yii::app()->end();
}
Then simply call at the end of your action:
$this->renderJSON($yourData);
Yii 2 has this functionality built-in, use the following code at the end of your controller action:
Yii::$app->response->format = \yii\web\Response::FORMAT_JSON;
return $data;
Upvotes: 97
Reputation: 7851
For Yii2 inside a controller:
public function actionSomeAjax() {
$returnData = ['someData' => 'I am data', 'someAnotherData' => 'I am another data'];
$response = Yii::$app->response;
$response->format = \yii\web\Response::FORMAT_JSON;
$response->data = $returnData;
return $response;
}
Upvotes: 20
Reputation: 367
In the controller action that you want to render JSON data, e.g: actionJson()
public function actionJson(){
$this->layout=false;
header('Content-type: application/json');
echo CJSON::encode($data);
Yii::app()->end(); // equal to die() or exit() function
}
See more Yii API
Upvotes: 0
Reputation: 2694
class JsonController extends CController {
protected $jsonData;
protected function beforeAction($action) {
ob_clean(); // clear output buffer to avoid rendering anything else
header('Content-type: application/json'); // set content type header as json
return parent::beforeAction($action);
}
protected function afterAction($action) {
parent::afterAction($action);
exit(json_encode($this->jsonData)); // exit with rendering json data
}
}
class ApiController extends JsonController {
public function actionIndex() {
$this->jsonData = array('test');
}
}
Upvotes: 5
Reputation: 3998
one more simple way by using
echo CJSON::encode($result);
example code:
public function actionSearch(){
if (Yii::app()->request->isAjaxRequest && isset($_POST['term'])) {
$models = Model::model()->searchNames($_POST['term']);
$result = array();
foreach($models as $m){
$result[] = array(
'name' => $m->name,
'id' => $m->id,
);
}
echo CJSON::encode($result);
}
}
cheers :)
Upvotes: 1
Reputation: 627
Yii::app()->end()
I think this solution is not the best way to end application flow, because it uses PHP's exit()
function, witch means immediate exit from execution flow. Yes, there is Yii's onEndRequest
handler, and PHP's register_shutdown_function
but it still remains too fatalistic.
For me the better way is this
public function run($actionID)
{
try
{
return parent::run($actionID);
}
catch(FinishOutputException $e)
{
return;
}
}
public function actionHello()
{
$this->layout=false;
header('Content-type: application/json');
echo CJavaScript::jsonEncode($arr);
throw new FinishOutputException;
}
So, the application flow continues to execute even after.
Upvotes: -1
Reputation: 48256
$this->layout=false;
header('Content-type: application/json');
echo CJavaScript::jsonEncode($arr);
Yii::app()->end();
Upvotes: 19
Reputation: 911
$this->layout=false;
header('Content-type: application/json');
echo json_encode($arr);
Yii::app()->end();
Upvotes: 10