CODEWITHSUNDEEP
javaargument-passing
me sung
me sung

Reputation: 73

Java code, passing arguments to method

I'm not sure what I did wrong here, this is my code 

package methods;

public class example {
    public static int sum(int x, int y){ 
        return x+y; 
    }
    public static void printSomething() {
        int a = 1; 
        int b = 2; 
        System.out.println("The sum of "+ x + " and "+ y +" is "+sum(a,b)); 
    }
    public static void main(String[] args) {
        System.out.println("Hello"); 
        printSomething();
    }
}

I want to print the sum of x and y is 3

Upvotes: 1

Views: 114

Answers (3)

xkothe
xkothe

Reputation: 674

package methods;

public class example {
    public static int sum(int x, int y){ 
        return x+y; 
    }
    public static void printSomething() {
        int a = 1; 
        int b = 2; 
        System.out.println("The sum of " + a + " and " + b + " is " + sum(a,b)); 
    }
    public static void main(String[] args) {
        System.out.println("Hello"); 
        printSomething();
    }
}

You can't access local variables (such as x, y of sum method) inside other method this way.

Upvotes: 0

Óscar López
Óscar López

Reputation: 236140

Try this:

System.out.println("The sum of "+ a + " and "+ b +" is "+sum(a,b));

The parameter names x and y are local to the method definition, in the current scope they're called a and b.

Alternatively, and for consistency's sake you could simply rename a and b to x and y in the printSomething() method. The result will be exactly the same, but now the variables will have the same name.

Upvotes: 2

droperto
droperto

Reputation: 152

I am not sure about what you want to achieve, but check if this helps:

package methods;

public class example {
    public static int sum(int x, int y){ 
        return x+y; 
    }
    public static void printSomething() {
        int a = 1; 
        int b = 2; 
        System.out.println("The sum of "+ a + " and "+ b +" is "+sum(a,b)); 
    }
    public static void main(String[] args) {
        System.out.println("Hello"); 
        printSomething();
    }
}

Upvotes: 0

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