CODEWITHSUNDEEP
pythondjangodjango-templates
lithiium
lithiium

Reputation: 647

Django - custom representation of a field in templates

I would like to have a field in my model which representation is automatically adjusted based in its value. Suppose I have this toy model:

class Article(models.Model):
    title = models.CharField(max_lenght=256)
    visits = models.PositiveIntegerField(default=0)

I would like to write in my templates just {{article.visits}} and, if the value is (for example), 45, it will render "45", but if the value is 1233, it will print "1.2k".

This is simple using template filters for formating, but I would like to do it automatically in any case. is it possible? What do you suggest?

Upvotes: 0

Views: 498

Answers (1)

catavaran
catavaran

Reputation: 45575

Add a property to the Article model:

class Article(models.Model):
    ...
    @property
    def visits_display(self):
        return self.visits if visits < 1000 else '%.1fk' % (self.visits/1000.0)

And use this property in the template:

{{ article.visits_display }}

Upvotes: 3

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