Reputation: 125
In JQuery, I am trying to drag an element from Draggable to a Droppable table with several cells, then drag the element between these cells as in this demo http://fiddle.jshell.net/c6vL61fb/4/
However, I got a problem that the element only be positioned automatically for the first time when move from draggable to droppable table, but not after that from a cell to the other cell. How can I fix the problem. Thank you very much.
HTML
<div id="products">
<div class="ui-widget-content">
<img id="photo1" class="product" src="http://s4.postimg.org/fh1l9dae1/high_tatras_min.jpg" width="96" height="72">
</div>
</div>
<div id="cont">
<p>Container</p>
<table id="container" width="100%" border="1">
<tr height="100px">
<td id='hello1' class='hello ui-widget-content' width="50%"> </td>
<td id='hello2' class='hello ui-widget-content' width="50%"> </td>
</tr>
<tr height="100px">
<td id='hello3' class='hello ui-widget-content' width="50%"> </td>
<td id='hello4' class='hello ui-widget-content' width="50%"> </td>
</tr>
</table>
</div>
Javascript
$(function () {
$(".hello")
.droppable({
activeClass: "ui-state-default",
hoverClass: "ui-state-hover",
drop: function(event, ui) {
var self = $(this);
var productid = ui.draggable.attr("id");
if (self.find("[id=" + productid + "]").length) return;
$(this).append($(ui.draggable).clone());
var cartid = self.closest('.hello').attr('id');
$(".hello:not(#"+cartid+") [id="+productid+"]").remove();
}
})
.sortable();
$(".product").draggable({
appendTo: 'body',
helper: 'clone'
});
});
Upvotes: 1
Views: 1017
Reputation: 24276
You just need to remove the style when dropping the element. So the following line:
$(this).append($(ui.draggable).clone());
must be changed to
$(this).append($(ui.draggable).clone().removeAttr('style'));
Upvotes: 2