Reputation: 5
I'm reading the template section on C++Primer recently, and i want to try it on my VS2013. I write a template find as following.
#include <vector>
template <typename iteratorT, typename valT>
iteratorT find(const iteratorT &up, const iteratorT &end, const valT &val)
{
auto iter = up;
while (iter != end && *iter != val)
++iter;
return ++iter;
}
int main()
{
std::vector<int> v{ 1, 2, 3, 4, 5, 6, 7, 8, 9 };
auto i = find(v.cbegin(), v.cend(), 7);
}
but visual studio tell me
1 IntelliSense: more than one instance of function template "find" matches the argument list:
function template "_InIt std::find(_InIt _First, _InIt _Last, const _Ty &_Val)"
function template "iteratorT find(const iteratorT &up, const iteratorT &end, const valT &val)"
argument types are: (std::_Vector_const_iterator<std::_Vector_val<std::_Simple_types<int>>>, std::_Vector_const_iterator<std::_Vector_val<std::_Simple_types<int>>>, int) d:\Projects\ConsoleApplication1\ConsoleApplication1\Source.cpp 16 11 ConsoleApplication1
I'm confused, I didn't use "using namespace std", can anyone tell me why will the std version of "find" come here ?
I'll be grateful for your help :D.
Upvotes: 0
Views: 63
Reputation: 55887
In vector
header file algorithm
is included.
Due ADL
find in namespace std
will be used since vector::const_iterator
is in std
namespace. Same will be with gcc
and clang
, if algorithm
header file is included manually.
Upvotes: 1