CODEWITHSUNDEEP
c++templates
syko
syko

Reputation: 3637

How can I specialize template function for a type in Parameter lists

My code snippet follows...

struct ParameterLists1 {
 typedef int key_type;
 typedef char value_type;
}

class A { ~~ };

struct ParameterLists2 {
 typedef A key_type;
 typedef int value_type;
}

template<P>
class Mine {
 typedef typename P::key_type key_type;
 typedef typename P::value_type value_type;

 void foo(key_type k, value_type v) {
       ~~ do something ~~
   if key_type is 'class A'
       key.special_function_in_A (k);
 }
 private:
   key_type key;
   value_type val;
}

I'd like to make call a function of 'class A' only when the key_type is the same with 'class A'. key_type can be char, int and 'class A'. class A has its own function 'special_function_in_A' which int or char do not have. It makes compile error. How can I resolve it?

Thank you :D

Upvotes: 0

Views: 36

Answers (1)

David G
David G

Reputation: 96810

Use tag-dispatching. The call site would look like this:

~~ do something ~~
do_something_else(key, k, std::is_same<key_type, A>());

Where do_something_else is defined as:

template<typename T>
void do_something_else(key_type&, key_type&, std::false_type) { }

template<typename T>
void do_something_else(key_type& key, key_type& k, std::true_type)
{
    key.special_function_in_A(k);
}

Upvotes: 1

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