CODEWITHSUNDEEP
pythonpandasanaconda
Team
Team

Reputation: 557

Why I can't use matplotlib.pyplot in Spyder?

I'm taking an online course. In the exercise I have to plot two histogram comparing rain vs no rain ridership, here is the code I used in online course.

import numpy as np
import pandas
import matplotlib.pyplot as plt

def entries_histogram(turnstile_weather):

    plt.figure()
    ax = turnstile_weather['ENTRIESn_hourly'][turnstile_weather['rain'] == 0].plot(kind = 'hist', title = 'Histogram of ENTRIESn_hourly', bins = 30)
    turnstile_weather['ENTRIESn_hourly'][turnstile_weather['rain'] == 1].plot(kind = 'hist', bins = 30, ax=ax)
    ax.set_ylabel('Frequency')
    ax.set_xlabel('ENTRIESn_hourly')
    return plt

It works perfect in the webpage of online course but when I installed Anaconda and use Spyder software to run the exact same code. It shows me an error:

C:\Anaconda3\lib\site-packages\pandas\tools\plotting.py in plot_series(series, label, kind, use_index, rot, xticks, yticks, xlim, ylim, ax, style, grid, legend, logx, logy, secondary_y, **kwds)
   2231         klass = _plot_klass[kind]
   2232     else:
-> 2233         raise ValueError('Invalid chart type given %s' % kind)
   2234 
   2235     """

ValueError: Invalid chart type given hist

Why?

Upvotes: 3

Views: 4232

Answers (1)

cel
cel

Reputation: 31339

Quick answer: You can fix the problem by updating pandas to the latest version:

conda install pandas

The kind='hist' option was added to Series.plot() in version 0.15.0. Your code example should work with latest version 0.15.2

For more information, see the enhancement section of the release notes of 0.15.0 and the pull request 7809 on github.

Upvotes: 2

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